Question

A binomial experiment has 4 trials in which p = 0.4. What is the probability of 3 successes?

Answer 1

The probability of 3 successes is 0.0384

How to determine the probability?

The given parameters are:

• Trials,  n = 4
• Probability of success, p = 0.4

The binomial probability is represented as:

$P(x) = ^nC_x * p^x * (1 - p)^{n-x$

So, the probability of three successes is:

$P(3) = ^4C_3 * 0.4^3 * (1 - 0.4)^{4 -3$

Evaluate the factors in the expression

$P(3) = ^4C_3 * 0.0384$

Evaluate the combination expression

P(3) = 1 * 0.0384

Evaluate the product

P(3) = 0.0384

Hence, the probability of 3 successes is 0.0384

Read more about probability at:

brainly.com/question/25870256

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