Hiii need help I'm in exam

Mathematics

1 answer:

Gnesinka [82]3 years ago

8 0

8x^2 plus 8x , use the box method ! It is very helpful for area and any other multiplication

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What is the slope of the line that passes through the points (-6, 8)(−6,8) and (-16, 33) ?(−16,33)?HELPPPPP!!!!

Marina CMI [18]

Answer:

It should be -5/2 for the points (-6,8) (-16,33)

Step-by-step explanation:

5 0

3 years ago

What are the solutions to x^2 + 8x + 7 = 0

Oksana_A [137]

So to solve this you need to reverse factor this problem

x^2 + 8x + 7 = 0

The common formula is this for factoring ax^2 + bx + c

Now you have to think what multplties to "c" and adds up to "b".

So in this case it's 7 x 1 = 7 and 7 + 1 = 8

So you set it up like this

(x + 7)(x + 1) = 0

So now you can check the factors by multiplying them together and see if it gets your original equation which is does.

So finally to get the answers you need to set each parenthesis to 0 and solve for x.

x + 7 = 0

x + 1 = 0

and we get x = -1 and - 7

You can also plug these two answers back into your original equation to see if it equals 0.

If you have any questions please feel free to comment

7 0

3 years ago

What is y divided by 2; y=4

shusha [124]

Y/2=?
y=4
4/2=2
so y divided by 2 is 2.
Have a nice day!!~~~ ^-^

4 0

3 years ago

Antonio is in a bowling league. His goal is to score an average of at least 100 points per game. His scores so far are 105,95,97

Nataliya [291]

He need to score a 67 to get to his goal hope I helped you out sorry if I get it wrong for you

5 0

3 years ago

What is the explicit rule for this geometric sequence? 4,45,425,4125,…

gregori [183]

You did not write the question correctly but I will try to answer the question according to 2 possible interpretations of your question.

Case 1:

Given the geometric sequence:

$4,\ \frac{4}{5} ,\ \frac{4}{25} ,\ \frac{4}{125} ,\ .\ .\ .$

Common ratio is given by $r= \frac{2nd\ term}{1st\ term} = \frac{ \frac{4}{5} }{4} = \frac{1}{5}$

The explicit rule of a geometric sequence is given by $T_n=ar^{n-1}$

Therefore, the explicit rule of the given sequence is $T_n=4\left( \frac{1}{5} \right)^{n-1}\ or\ 20\left( \frac{1}{5} \right)^n$

Case 2:

Given the geometric sequence:

$4,\ 4\cdot5,\ 4\cdot25,\ 4\cdot125,\ .\ .\ .$

Common ratio is given by $r= \frac{2nd\ term}{1st\ term} = \frac{4\cdot5}{4} = 5$

The explicit rule of a geometric sequence is given by $T_n=ar^{n-1}$

Therefore, the explicit rule of the given sequence is $T_n=4(5)^{n-1}\ or\ \frac{4}{5}(5)^n$

4 0

3 years ago

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Hiii need help I'm in exam​

Hiii need help I'm in exam