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3 years ago

Monica reads a 7 1/2 pages of a mystery book in 9 minutes. What is her average reading rate in pages per minute?

Mathematics

2 answers:

zaharov [31]3 years ago

7 0

Answer: 5/6 pages per minute

Explanation:

1.) set up problem

7 1/2 ÷ 9

2.) make 7 1/2 an improper fraction by multiplying 7 by the denominator of 1/2 and adding it to the numerator

15/2 ÷ 9

3.) flip the division sign to a multiplication sign and set a 1 over 9

15/2 • 1/9

4.) multiply

15/28

5.) simplify

5/6

mrs_skeptik [129]3 years ago

6 0

Answer:

7.5 pages/9 mins

=(5/6) pages/minute

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What are the relative frequencies, to the nearest hundredth, of the rows of the two-way table?

sveta [45]

Answer: A B

Group 1 0.25 0.75

Group 2 0.44 0.56

Step-by-step explanation:

Since we have given that

Number of people of A in group 1 = 15

Number of people of B in group 1 = 45

Total number of people in group 1 is given by

$15+45=60$

Relative frequency of people of A in Group 1 is given by

$\frac{15}{60}=0.25$

Relative frequency of people of B in Group 1 is given by

$\frac{45}{60}=0.75$

Similarly, Number of people of A in group 2 = 20

Number of people of B in group 2 = 25

Total number of people in group 2 is given by

$20+25=45$

Relative frequency of people of A in Group 2 is given by

$\frac{20}{45}=0.44$

Relative frequency of people of B in Group 2 is given by

$\frac{25}{45}=0.56$

Hence, A B

Group 1 0.25 0.75

Group 2 0.44 0.56

6 0

3 years ago

The table shows how many books the students in Bergdalsskolan list during the summer. There were 48 students who list 4 books. a

Juliette [100K]

Step 1:

First, find the total number of students.

Let the total number of students = m

Step 2:

Find the total number of students using the percentage of 4 books.

48 students listed 4 books with a percentage of 16%

$\begin{gathered} 48\text{ = 16\% of m} \\ 48\text{ = }\frac{16}{100}\text{ }\times\text{ m} \\ 48\text{ = }\frac{16m}{100} \\ \text{Cross multiply} \\ 16m\text{ = 48 }\times\text{ 100} \\ 16m\text{ = 4800} \\ \text{m = }\frac{4800}{16} \\ \text{m = 300} \end{gathered}$

Hence, there are 300 students.

$\begin{gathered} \text{Number of students that had 1 book = 24\% of 300} \\ =\text{ }\frac{24}{100}\text{ }\times\text{ 300} \\ =\text{ }\frac{7200}{100} \\ =\text{ 72 students} \end{gathered}$

72 students had 1 book.

b) What percentage more read 2 books than 4 books?

percentage that read 2 books = 36%

percentage that read 4 books = 16%

36 - 16 = 20%

There are 20% students that read 2 books than 4 books.

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1 year ago

Can someone help me with my math ?

shepuryov [24]

Easy! Just substitute.

That will be 3 + 8 * 4

Remember PEMDAS? Multiplication comes before addition, so FIRT MULTIPLY.

3+ 32= 35
Final answer= 35

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