So if the formula is A=(pi)r^2, find the area of the entire circle:
A=(pi)(13^2)=530.66cm
then find the area of the little circle:
A=(pi)(3^2)= 28.26cm
then subtract the little circle from the big circle:
530.66cm-28.26cm= 502.4cm
and there you go. Hope this helps!
The best form to use is standard form, which is, y=ax^2+bx=+c.
The answer is one because according to pemdas you must do the parentheses first then do the rest
Answer
The steel ball will be caught up in between the mercury and water medium.
Step-by-step explanation:
- Mercury with a density of 13546 kg/m^3
- water with a density of 1000 kg/m^3
- Steel with a density of 8050 kg/m^3
From the factual density of both substances given above ,it shows that mercury is more heavier than water. In that case mercury will be at the lower layer when mixed with water.
The steel ball will be caught in between both mixtures as the density of steel is 8050 kg/m^3.Which is more than Water but less than Mercury.
Use pythagoras
d = √(Δx² + Δy²)
d = √(12-2)² + (9-4)²
d = √(10² + 5²)
d = √(100 + 25)
d = √125
d = 5√5
d = 5 × 2.236
d = 11.18
The nearest tenth is 11.2, so the distance is near to 11.2
