Question:
If a sample of 2 hammer is selected
(a) find the probability that all in the sample are defective.
(b) find the probability that none in the sample are defective.
Answer:
a 
b 
Step-by-step explanation:
Given
--- hammers
--- selection
This will be treated as selection without replacement. So, 1 will be subtracted from subsequent probabilities
Solving (a): Probability that both selection are defective.
For two selections, the probability that all are defective is:
Solving (b): Probability that none are defective.
The probability that a selection is not defective is:
For two selections, the probability that all are not defective is:
The total fabric Morgan needs to cover the cushions will be 19.64 square feet.
It is given that each cushion has a circumference of 7.85 feet.
It is known that the circumference of a circle = 2πr, where 'r' is the radius of the circle.
2πr = 7.85
r = 1.25
<h3>What is an area of a circle?</h3>
area of a circle is πr².
now, we can calculate the area = π× 1.25² = 4.91 square feet
since each circular cushion has two circular faces so the total number of faces Morgan needs to cover will be 4.
Therefore, the total fabric needed= 4×4.91 = 19.64 square feet.
to get more about the area of a circle, refer to the link:
brainly.com/question/12069107
Answer:
Fraction of bread used in the recipe is 3/12 which can be further simplified into 1/4
Explanation:
The original loaf of bread is 100% complete (no fraction is taken from it yet). This means that the value of the original loaf is 12/12
Now, assume that the fraction used in the recipe is x
We know that:
2/12 of the loaf was used in making a sandwich
7/12 of the oaf was put in the refrigerator
Therefore:
complete loaf = fraction used in making a sandwich + fraction used in making recipe + fraction put in refrigerator
12/12 = x + 2/12 + 7/12
12/12 = x + 9/12
x = 12/12 - 9/12
x = 3/12
Hope this helps :)
The saying "A picture is worth a thousand words" comes to mind here. You can list all of the possible points in a solution region, or you can list a few points to give the general pattern. Though this method requires a bit more work than simply graphing and showing the solution shaded region. A visual is often more efficient at conveying a message especially to those who aren't proficient with algebra. I'm sure there are other reasons why graphs are the better choice, but that's all I could think of really.
