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vodka [1.7K]
2 years ago
7

Which of the following is the domain and range of the ellipse with equation x2 + 4y2 – 2x + 16y – 19 = 0?

Mathematics
1 answer:
Nata [24]2 years ago
5 0

The option second D: [–5, 7]; R: [–5, 1] is correct the domain is D: [–5, 7], and the range is R: [–5, 1]

<h3>What is an ellipse?</h3>

An ellipse is a locus of a point that moves in a plane such that the sum of its distances from the two points called focus adds up to a constant. It is taken from the cone by cutting it at an angle.

We have an ellipse equation:

\rm x^{2}+4y^{2}-2x+16y-19=0

We can write the above equation as:

\rm \dfrac{\left(x-1\right)^{2}}{36}+\dfrac{\left(y+2\right)^{2}}{9}=1

The domain will be:

D: [–5, 7]

The range will be:

R: [–5, 1]

Thus, the option second D: [–5, 7]; R: [–5, 1] is correct the domain is D: [–5, 7] and the range is R: [–5, 1]

Learn more about the ellipse here:

brainly.com/question/19507943

#SPJ1

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Given: f(x) = 2x-1 and g(x) = 2x-3<br> Find:<br> (fog)(x)<br> HELP PLEASEE!!
Murljashka [212]

Answer:

(fog)(x) = 4x - 7

Step-by-step explanation:

f(x) = 2x-1 and g(x) = 2x-3;

(fog)(x) = f(g(x)

= f(2x - 3) = 2(2x - 3) - 1

= 4x - 6 - 1

= 4x - 7

7 0
3 years ago
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yuradex [85]

Answer:

B (1 , 3) , D (1 , -2)

Step-by-step explanation:

∵ A (-3 , 3) , C (-3 , -2)

∵ They have the same x-coordinate

∴ AC is a vertical segment its length = 3 - -2 = 5

∵ The area of the rectangle = 20

∴ The width of it = 20 ÷ 5 = 4

∴ x-coordinate of B: -3 + 4 = 1

∴ y-coordinate of B : 3 ⇒ AB horizontal segment

∴ B (1 , 3)

∵ x-coordinate of BD is 1 ⇒ BD is vertical segment

∵ y-coordinate = 3 - 5 = -2

∴ D (1 , -2)

3 0
3 years ago
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Which pair of points on a coordinate plane are separated by a distance of 5 units?
icang [17]

Answer:

(0,0) and (5,0)

Step-by-step explanation:

i dont know your choices

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3 years ago
How would you correctly write the equation 4(10+5)=6(12-2) using the distributive property?
slamgirl [31]

the correct answer is 45=70

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3 years ago
Math help questions <br>​
Evgen [1.6K]

After 1 year, the initial investment increases by 7%, i.e. multiplied by 1.07. So after 1 year the investment has a value of $800 × 1.07 = $856.

After another year, that amount increases again by 7% to $856 × 1.07 = $915.92.

And so on. After t years, the investment would have a value of \$800 \times 1.07^t.

We want the find the number of years n such that

\$856 \times 1.07^n = \$1400

Solve for n :

856 \times 1.07 ^n = 1400

1.07^n = \dfrac74

\log_{1.07}\left(1.07^n\right) = \log_{1.07}\left(\dfrac74\right)

n \log_{1.07}(1.07) = \log_{1.07} \left(\dfrac74\right)

n = \log_{1.07} \left(\dfrac74\right) = \dfrac{\ln\left(\frac74\right)}{\ln(1.04)} \approx \boxed{8.3}

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