8. Paris used a semicircle, a rectangle, and a right triangle to form the figure shown.

Mathematics

1 answer:

umka2103 [35]2 years ago

8 0

= option J

area of figure = 1/2 × 6× 4 + 8×6 + 3.14× 9/2

= 12+ 48 + 3.14× 4.5

= 60+ 14.13

= 74.13 cm²

option J

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hope this will be helpful to you.

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Given: <SPT = <RQT, ST = RT Prove: PR = QS

andrey2020 [161]

Answer:

See explanation

Step-by-step explanation:

Consider triangles PTS and QTR. In these triangles,

$ST=RT$ - given;
$\angle SPT=\angle RQT$ - given;
$\angle STP=\angle RTQ$ - as vertical angles when lines PR and SQ intersect.

Thus, $\triangle PTS\cong \triangle QTR$ by AAS postulate.

Congruent triangles have congruent corresponding sides, so

$PT=QT$

Consider segments PR and QS:

$PR=PT+TR\ [\text{Segment addition postulate}]\\ \\QS=QT+TS\ [\text{Segment addition postulate}]\\ \\PT=QT\ [\text{Proven}]\\ \\ST=RT\ [\text{Given}]$

So,

$PR=SQ\ [\text{Substitution property}]$

7 0

2 years ago

Which function has the same domain as y=2 sqrt x

Fiesta28 [93]

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We can't take the square root of negative numbers (ignoring imaginary numbers), so that means we can take the square root of any non-negative number; i.e. we can take the square root of zero, and any positive number.
Therefore, any function that can take in values of x that are zero or more than zero has the same domain as the given function. So $y=\sqrt{x}$ is a function that has the same domain as $y=2\sqrt{x}$ .