Step-by-step explanation:
Original x-value = 21
New x-value = 21 * (-1/7) = -3.
Original y-value = 28
New y-value = 28 * (-1/7) = -4.
Hence the coordinates of the new point is (-3,-4).
I think it's the third one too
Hi, thank you for posting your question here at Brainly.
The general equation of a horizontal ellipse is
(x-h)2/a2 + (y-k)2/b2 = 1, at center (h,k) while a = semi-major axis, b = semi-minor axis. These are related through the distance of the focus from the center,c. a2 = b2 + c2.
If you draw the points on a coordinate plane, the center of the ellipse is at (0,0), so h and k equals 0. Then, the minor axis (2b) spans from 8 to -8 of the y-axis. This is equal to 16 units. Hence,
2b = 16
b = 8
b^2 = 64
The distance between the two foci is 2c. Thus,
2c = 12
c = 6
c^2 = 36
Then, a2 = 64 + 36 = 100. Substituting to the general equation:
x^2/100 + y^2/64 = 1
Two numbers that multiply to -2 could be
-1 and 2
Or
-2 and 1.
Since -1+2=1, -1 and 2 are the numbers you are looking for.
Hope this helps!
If x is the first integer, then x+1 is the second. x(x+1)=132 or x^2+x-132=0. This factors as (x-11)(x+12)=0. Thus either x=11 or x=-12
<span>So either 11 and 12 or -12 and -11 will do.</span>
