The probability of one arrives within the next 10 minutes
when he already been waiting for one jour for a taxi is,
P (X > 70 | X > 60) = P (X > 10) = 1 – P (X ≤ 10)
= 1 – {1 – e ^ -((1 / 10) 10)} = e ^ -1
= 0.3679
The probability of one arrives within the next 10 minutes
when he already been waiting for one hour for a taxi is 0.3679
Answer:
Step-by-step explanation:
The answer for your question is 4x^2-15x+6+ 2/3x+5
The answer is what is shown on the phone
