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Goshia [24]
3 years ago
14

The sum of interior angles of a regular polygon is 1080.Find the size of each exterior angle

Mathematics
1 answer:
svetoff [14.1K]3 years ago
8 0

Answer:

45

Step-by-step explanation:

Calculation to Find the size of each exterior angle

First step is to calculate the sum of interior angles of a polygon using this formula

Sum of interior angles of a polygon =S=(n-2)*180

Let plug in the formula

Sum of interior angles of a polygon=1080=(n-2)*180

Cross multiply

1080/180=n-2

6=n-2

Add 2 to both sides

6+2=n-2+2

n=8

Now let Find the size of each exterior angle using this formula

Size of each exterior angle=360/n

Where,

n represent numbers of sides of the polygon

Let plug in the formula

Size of each exterior angle=360/8

Size of each exterior angle=45

Therefore the size of each exterior angle will be 45

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marin [14]

i. 171

ii. 162

iii. 297

Solution,

n(U)= 630

n(I)= 333

n(T)= 168

i. Let n(I intersection T ) be X

333 - x + x + 468 - x = 630 \\ or \: 333 + 468 - x = 630 \\ or \: 801 - x = 630 \\ or \:  - x = 630 - 801 \\ or \:  - x =  - 171 \\ x = 171

<h3>ii.n(only I)= n(I) - n(I intersection T)</h3><h3> = 333 - 171</h3><h3> = 162</h3>

<h3>iii. n ( only T)= n( T) - n( I intersection T)</h3><h3> = 468 - 171</h3><h3> = 297</h3>

<h3>Venn- diagram is shown in the attached picture.</h3>

Hope this helps...

Good luck on your assignment...

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