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1 year ago

1. (08.01 MC) The graph shows two lines. A and B

Mathematics

1 answer:

Ivahew [28]1 year ago

6 0

Answer:

Part A:

A pair of linear equations can only have one solution or infinitely many solutions. In this case, there would only be one solution as they intersection at only one point.

Part B:

The solution would be (3, 4) because it is the point of intersection between the two linear lines.

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Find the explicit formula that produces the given sequence. <br> 3/2, 3/4, 3/8, 3/16,...

lara [203]

$\frac{3}{2};\ \frac{3}{4};\ \frac{3}{8};\ \frac{3}{16};\ ...\\\\a_1=\frac{3}{2}\\\\a_2=\frac{3}{4}=\frac{3}{2}\cdot\frac{1}{2}\\\\a_3=\frac{3}{8}=\frac{3}{4}\cdot\frac{1}{2}=\frac{3}{2}\cdot\left(\frac{1}{2}\right)^2\\\\a_4=\frac{3}{16}=\frac{3}{8}\cdot\frac{1}{2}=\frac{3}{2}\cdot\left(\frac{1}{2}\right)^3\\\vdots$
$a_n=\frac{3}{2}\cdot\left(\frac{1}{2}\right)^{n-1}=\frac{3}{2}\cdot\left(\frac{1}{2}\right)^{-1}\cdot\left(\frac{1}{2}\right)^n=\frac{3}{2}\cdot2\cdot\left(\frac{1}{2}\right)^n=3\cdot\left(\frac{1}{2}\right)^n$

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2 years ago

Determine the intercepts of the line.

Damm [24]

Y int.: (0,-1.2)
X int.: (-0.7,0)

6 0

2 years ago

Please can someone answer this.

ivanzaharov [21]

Answer:

• x = -4, x = 0, x = 1

Step-by-step explanation:

x is a factor of all terms, so x=0 is a zero. (Eliminates choices 1 and 5.)

The sum of coefficients is 0, so x=1 is a zero. (Eliminates choices 3 and 4.)

Reversing the sign of the odd-degree terms gives signs of -++, so there is one sign change, hence one negative real root (by Descartes' rule of signs). This confirms choice 2 as the answer.

___

Of course, your graphing calculator can answer this almost as quickly.

7 0

3 years ago

EASY WORK!!plz look at the photo and yes its easy for other people but not me for people asking.

ser-zykov [4K]

Answer:

Here's a way this can help! If the graph it by two then any odd number will by by the middle, start by the origin and you'll be able to see it clearly.

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3 years ago

Read 2 more answers

List the potential rational zeros of the polynomial function. Do not find the zeros.

Archy [21]

<span> $f(x)=\boxed{1}x^5-3x^2+3x+\boxed{14}$

</span>The potential rational zeros are divisors of 14:

$\pm1;\ \pm2;\ \pm7;\ \pm14$

and the quotient p/q where p is a divisor of 1, and q is a divisor of 14:

$\pm\dfrac{1}{2};\ \pm\dfrac{1}{7};\ \pm\dfrac{1}{14}$

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3 years ago