Answer
106 sio so you multiply first
1+1+2+3+4+5+6×15
1+1+2+3+4+5+90
then you add all of them then it will be 106
<span>At a corner gas station, the revenue R varies directly with the number g of gallons of gasoline sold. If the revenue is $44.50 when the number of gallons sold is 10, find a linear equation that relates revenue R to the number g of gallons of gasoline. Then find the revenue R when the number of gallons of gasoline sold is 15.5.
Solution:
As the question mentioned the direct relationship between the quantities, hence
10 gallons of gasoline sold = $44.50
15.5 gallons of gasoline sold = $x
by cross multiplication, we get that
10x = 15.5 * 44.50
which implies that
x = 68.975
Thus by $</span>68.975 revenue is obtained by selling 15.5 gallons of gasoline.
In order to evaluate the given function at x = -3, simply replace "x" in the function with -3 and solve.
<em>Multiply -4 and -3 in the function above.</em>
<em>Add 3 on both sides of the equation.</em>
<em>Add 2y on both sides of the equation.</em>
<em>Divide both sides of the equation by -3.</em>
Therefore, at x = -3, the value of y = -5. Hence, f(-3) = -5.
Answer:
f(-3) = -5
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The answer is B; at least, I am pretty sure that's the answer.
