Answer:
The maximum potential energy of the child will be maximum at the two end points.
The maximum kinetic energy of the <em>child </em>occurs at the lowest point of the swing.
The potential energy of the child depends on the displacement of the child.
P.E = mgh
The maximum height attained occurs at the two end points of her swing motion.
Thus, the maximum potential energy of the child will be maximum at the two end points.
The kinetic energy of the child depends on the velocity of the child
K.E = ¹/₂mv²
The maximum velocity of the swing occurs at the lowest point of the swing.
Thus, the maximum kinetic energy of the child occurs at the lowest point of the swing.
Hope this helps!
Answer is: there is 3,36 micrograms of iron in <span>sample of Greg's blood.
</span>m(Fe) = 42 mcg(micrograms).
V(Fe) = 1 dL = 1 dL · 100 mL/1dL.
V(Fe) = 100 mL.
Make proportion: m(Fe) : 8 mL = 42 mcg : 100 mL.
100 mL · m(Fe) = 8 mL · 42 mcg.
m(Fe) = 336 mL·mcg ÷ 100 mL.
m(Fe) = 3,36 mcg.
Answer:
The correct answer is A) single
Explanation:
In the case of the Bromo atom, it requires 1 electron to complete its octet, therefore it shares 1 electron with the other Bromo atom.
<u>Answer:</u> The potential of electrode is -0.79 V
<u>Explanation:</u>
When zinc is dipped in zinc sulfate solution, the electrode formed is 
Reduction reaction follows: 
To calculate the potential of electrode, we use the equation given by Nernst equation:
![E_{(Zn^{2+}/Zn)}=E^o_{(Zn^{2+}/Zn)}-\frac{0.059}{n}\log \frac{[Zn]}{[Zn^{2+}]}](https://tex.z-dn.net/?f=E_%7B%28Zn%5E%7B2%2B%7D%2FZn%29%7D%3DE%5Eo_%7B%28Zn%5E%7B2%2B%7D%2FZn%29%7D-%5Cfrac%7B0.059%7D%7Bn%7D%5Clog%20%5Cfrac%7B%5BZn%5D%7D%7B%5BZn%5E%7B2%2B%7D%5D%7D)
where,
= electrode potential of the cell = ?V
= standard electrode potential of the cell = -0.76 V
n = number of electrons exchanged = 2
(concentration of pure solids are taken as 1)
![[Zn^{2+}]=0.1M](https://tex.z-dn.net/?f=%5BZn%5E%7B2%2B%7D%5D%3D0.1M)
Putting values in above equation, we get:

Hence, the potential of electrode is -0.79 V