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KATRIN_1 [288]
2 years ago
15

Combustion reactions are ones that always include elemental oxygen as a reactant. When a hydrocarbon (substance made up of carbo

n and hydrogen) reacts with oxygen, the products of the combustion reaction are carbon dioxide and water.
Drag and drop the products to the correct reactants for these combustion reactions. The reactants have the correct coefficients for making balanced reactions.

Chemistry
1 answer:
inysia [295]2 years ago
5 0

1. CH4 + 2O2 = CO2 + 2H20                 B.

2. 2CH2H6 + 7O2 = 4CO2 + 6H20      A  

3. C3H8 + 502 = 3CO2 + 4H20            C

<h3>
How to determine the appropriate products of reaction</h3>

To find the appropriate end products, use the following rules

  • The hydrogen ratio should be the same on both the product and reactant sides
  • The oxygen ratio should be the same on both the product and reactant sides
  • The carbon ratio should be the same on both sides.

Thus for equation;

1. CH4 + 2O2 = CO2 + 2H20                 B.

2. 2CH2H6 + 2O2 = 4CO2 + 6H20      A  

3. C2H8 + 502 = 2CO2 + 4H20            C  

Learn more about balancing equations here:

brainly.com/question/26694427

#SPJ1

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A child is swinging back and forth on a swing. Changes in her kinetic and potential energy are happening each moment. At which p
dedylja [7]

Answer:

The maximum potential energy of the child will be maximum at the two end points.  

The maximum kinetic energy of the <em>child </em>occurs at the lowest point of the swing.  

The potential energy of the child depends on the displacement of the child.  

P.E = mgh  

The maximum height attained occurs at the two end points of her swing motion.  

Thus, the maximum potential energy of the child will be maximum at the two end points.

The kinetic energy of the child depends on the velocity of the child  

K.E = ¹/₂mv²  

The maximum velocity of the swing occurs at the lowest point of the swing.  

Thus, the maximum kinetic energy of the child occurs at the lowest point of the swing.

Hope this helps!

5 0
3 years ago
Read 2 more answers
How many micrograms of iron were in the 8.0 mL sample of Greg's blood?
Alenkinab [10]
Answer is: there is 3,36 micrograms of iron in <span>sample of Greg's blood.
</span>m(Fe) = 42 mcg(micrograms).
V(Fe) = 1 dL = 1 dL · 100 mL/1dL.
V(Fe) = 100 mL.
Make proportion: m(Fe) : 8 mL = 42 mcg : 100 mL.
100 mL · m(Fe) = 8 mL · 42 mcg.
m(Fe) = 336 mL·mcg ÷ 100 mL.
m(Fe) = 3,36 mcg.
4 0
3 years ago
In the molecule Br2, how many bonds would be present between the two atoms of Br
Evgesh-ka [11]

Answer:

The correct answer is A) single

Explanation:

In the case of the Bromo atom, it requires 1 electron to complete its octet, therefore it shares 1 electron with the other Bromo atom.

8 0
3 years ago
Which type of molecule is shown below?<br> O A. Alkane<br> B. Alkyne<br> C. Aromatic<br> D. Alkene
V125BC [204]

Answer:

alkyne molecules is shown

3 0
3 years ago
Read 2 more answers
A zinc rod is placed in 0.1 MZnSO4 solution at 298 K. Write the electrode reaction and calculate the potential of the electrode.
yanalaym [24]

<u>Answer:</u> The potential of electrode is -0.79 V

<u>Explanation:</u>

When zinc is dipped in zinc sulfate solution, the electrode formed is Zn^{2+}(aq.)/Zn(s)

Reduction reaction follows:  Zn^{2+}(0.1M)+2e^-\rightarrow Zn(s);(E^o_{Zn^{2+}/Zn}=-0.76V)

To calculate the potential of electrode, we use the equation given by Nernst equation:

E_{(Zn^{2+}/Zn)}=E^o_{(Zn^{2+}/Zn)}-\frac{0.059}{n}\log \frac{[Zn]}{[Zn^{2+}]}

where,

E_{cell} = electrode potential of the cell = ?V

E^o_{cell} = standard electrode potential of the cell = -0.76 V

n = number of electrons exchanged = 2

[Zn]=1M    (concentration of pure solids are taken as 1)

[Zn^{2+}]=0.1M

Putting values in above equation, we get:

E_{cell}=-0.76-\frac{0.059}{2}\times \log(\frac{1}{0.1})\\\\E_{cell}=-0.79V

Hence, the potential of electrode is -0.79 V

4 0
3 years ago
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