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3 years ago

Which bond is the strongest CO CF CN CC?

Chemistry

1 answer:

romanna [79]3 years ago

3 0

Answer:

The CN double bond and triple bond are stronger than the corresponding CC bonds

Explanation:

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Need help with number 17 pleasee

kap26 [50]

Answer:

I'm pretty sure the answer is D, I could be wrong tho

3 0

3 years ago

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A chunk of zinc is added to a solution of gold (III) nitrate to extract the gold. The reaction forms,

alina1380 [7]

Answer:

it forms :

1. Gold ( Au )

2. Zinc nitrate ( Zn(NO3)2 )

Explanation:

When a chunk of zinc is added to a solution of gold (III) nitrate to extract the gold. The reaction forms Gold and Zinc nitrate .

it's a single displacement reaction,

here's the balanced equation for above reaction :

3 Zn + 2 Au(NO3)3 =》3 Zn(NO3)2 + 2 Au

7 0

3 years ago

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A gas has a volume of 420 L at a temperature of -42.0 degrees celsius. What volume will the gas occupy at 18.0 degrees celsius?

Hoochie [10]

Formula

V/T = V1/T1

Givens

V = 430 L

T = - 42 °C = - 42 + 273 = 231°K

V1 = ??

T1 = 18°C + 273 = 291°K

The pressure is a constant.

Solution

420/231 = V1/291 Multiply by 291

420*291 / 231 = V1

V1 = 122220 / 231

V1 = 521.1 L

6 0

4 years ago

If the percent yield for the following reaction is 75.0%, and 25.0 g of NO₂ are consumed in the reaction, how many grams of nitr

victus00 [196]

Answer:

17.1195 grams of nitric acid are produced.

Explanation:

$3NO_2+H_2O\rightarrow 2HNO_3+NO$

Moles of nitrogen dioxide :

$\frac{25.0 g}{56 g/mol}=0.5434 mol$

According to reaction 3 moles of nitrogen dioxides gives 2 moles of nitric acid.

Then 0.5434 moles of nitrogen dioxides will give:

$\frac{2}{3}\times 0.5434 mol=0.3623 mol$ of nitric acid.

Mass of 0.3623 moles of nitric acid :

$0.3623 mol\times 63 g/mol=22.8260 g$

Theoretical yield = 22.8260 g

Experimental yield = ?

$\%Yield=\frac{\text{Experimental yield}}{\text{theoretical yield}}\times 100$

$75\%=\frac{\text{Experimental yield}}{22.8260 g}$

Experimental yield of nitric acid = 17.1195 g

7 0

4 years ago

How many grams are in 2.5 moles of Carbon

Jet001 [13]

According to the periodic table, carbon's molar mass is 12.011 grams per mole (that's the small number under the element). So, just multiply like this to get the answer:

$(2.5\ mol\ C)(\frac{grams\ C}{12.011\ mol\ C})=0.20814\ g\ C$

So, there are approximately 0.208 grams in 2.5 moles of carbon.

6 0

3 years ago

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