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DanielleElmas [232]
3 years ago
6

In the lab you react 2.0 g of Na2CO3 with enough CaCl2. According to the reaction Na2CO3 + CaCl2 -> CaCO3 + 2NaCl How much Ca

CO3 will you produce?
Chemistry
1 answer:
vlada-n [284]3 years ago
3 0

Answer:

1.89 g CaCO₃

Explanation:

You will have to use stoichiometry for this question.  First, look at the chemical equation.

Na₂CO₃  +  CaCl₂  ==>  2 NaCl  +  CaCO₃

From the above equation, you can see that for one mole of Na₂CO₃, you will produce one mole of CaCO₃.  This means that however many moles of Na₂CO₃ you have in the beginning, you will have the same amount of moles  of CaCO₃, theoretically speaking.

So, convert grams to moles.  You should get 0.0189 mol Na₂CO₃.  This means that you will get 0.0189 mol CaCO₃.  I'm not sure what units you want the answer in, but I'm going to give it in grams.  Convert moles to grams.  Your answer should be 1.89 g.

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shtirl [24]

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Let us assume that the volume of given aqueous solution is 7.5 L.

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                C = \frac{P}{K_{h}}

where,   pressure (P) = 760 torr = 1 atm

According to Henry's law, constants for gases in water at 25^{o}C are as follows.

  p(O_{2}) = 0.21 atm = 0.21 bar

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   K_{h} for O_{2} = 7.9 \times 10^{2} bar/mol

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         n(O_{2}) = 7.5 \times 2.66 \times 10^-4 = 1.995 \times 10^-3 mol

         n(N_2) = 7.5 \times 4.875 \times 10^-4 = 3.66 \times 10^-3 mol

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Hence, mass of oxygen will be as follows.

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