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3 years ago

What is the range of the function y= √x+5

Mathematics

2 answers:

Fofino [41]3 years ago

5 0

Answer: {f(x)∈R∣f(x)≥0}

Step-by-step explanation: The square root function never produces a negative result. Therefore, for the function f(x)=√x+5 , the domain is {x∈R∣x≥−5} and the range is {f(x)∈R∣f(x)≥0} .

Tema [17]3 years ago

3 0

Answer:

Y>0

Step-by-step explanation:

To determine the range of this function, we must first evaluate the domain. The square root function is a nice, neat function as long as the radicand isn’t negative. In this function, the radicand becomes negative after x gets smaller than -5, so the domain of this function is [-5, infinity).

Now that we know the domain, we can calculate the range. Beginning with the left boundary, we can substitute -5 into the function to see what y equals at this x-value. At -5, y equals 0, so the minimum value for the range is 0; with the right boundary, substituting infinity yields infinity, so the range is any number greater than 0.

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Zoe is solving the equation 3x – 4 = –10 for x. She used the addition property of equality to isolate the variable term as shown

kherson [118]

3x-4 = -10

3x-4 +4 = -10 +4

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x = -6 : 3

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3 years ago

1. In a 30-60-90 triangle, the length of the hypotenuse is 6. What is the length of the shortest

PIT_PIT [208]

Answer:

b. 3

Step-by-step explanation:

In a 30°-60°-90° triangle, the short side is ½ the hypotenuse [the long side is double the short side].

30°-60°-90° Triangles

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3 years ago

Find the solution of the differential equation dy/dt = ky, k a constant, that satisfies the given conditions. y(0) = 50, y(5) =

irga5000 [103]

Answer: The required solution is $y=50e^{0.1386t}.$

Step-by-step explanation:

We are given to solve the following differential equation :

$\dfrac{dy}{dt}=ky~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)$

where k is a constant and the equation satisfies the conditions y(0) = 50, y(5) = 100.

From equation (i), we have

$\dfrac{dy}{y}=kdt.$

Integrating both sides, we get

$\int\dfrac{dy}{y}=\int kdt\\\\\Rightarrow \log y=kt+c~~~~~~[\textup{c is a constant of integration}]\\\\\Rightarrow y=e^{kt+c}\\\\\Rightarrow y=ae^{kt}~~~~[\textup{where }a=e^c\textup{ is another constant}]$

Also, the conditions are

$y(0)=50\\\\\Rightarrow ae^0=50\\\\\Rightarrow a=50$

and

$y(5)=100\\\\\Rightarrow 50e^{5k}=100\\\\\Rightarrow e^{5k}=2\\\\\Rightarrow 5k=\log_e2\\\\\Rightarrow 5k=0.6931\\\\\Rightarrow k=0.1386.$

Thus, the required solution is $y=50e^{0.1386t}.$

8 0

3 years ago

Read 2 more answers

A consumer survey indicates that the average household spendsμ= $185on groceries each week. The distribution of spending amounts

Vitek1552 [10]

Answer:

$P(X>200)=P(\frac{X-\mu}{\sigma}>\frac{200-\mu}{\sigma})=P(Z>\frac{200-185}{25})=P(Z>0.6)$

And we can find this probability using the complement rule and with the normal standard table or excel:

$P(Z>0.6)=1-P(z$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the average household spent of a population, and for this case we know the distribution for X is given by:

$X \sim N(185,25)$