Question

A discount book store sells hardcover books for $8 each and paperbacks for $4 each.The number of hardcover books, h, sold one day was 2 more than four times the number of paperback books, p, sold that same day. The total amount of sales for that day was $160. Jean-Paul wrote the following system of linear equations to find the number of each type of book sold.
8 h + 4 p = 160. p = 4 h + 2.

What is Jean-Paul’s error?
A. Jean-Paul should have written the first equation as h + p = 160.
B. Jean-Paul should have written the first equation as 4 h + 8 p = 160.
C. Jean-Paul should have written the second equation as h = 4 p + 2.
D. Jean-Paul should have written the second equation as p + 2 = 4 h.
it is not A.. see picture

Answer 1

Jean-Paul's error is that he should have written the second equation as h = 4 p + 2.

How to solve an equation?

The hardcover book is $8 each and paperbacks for $4 each.

The number of hardcover books, h, sold one day was 2 more than four times the number of paperback books, p, sold that same day.

Therefore,

h = 4p + 2

Hence,

8h + 4p = 160

Therefore, the right equation are as follows:

h = 4p + 2

8h + 4p = 160

Hence, Jean-Paul should have written the second equation as h = 4 p + 2.

learn more on equation here: brainly.com/question/8465417

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