The exponential equation that can model the value of the camper van , in x years is y = 38000*(0.85)ˣ .
In the question ,
it is given that
the present value of the camper van (P₀) = $38000
given the depreciation rate is 15% each year (r)= -0.15
The future value y ,of the camper van can be given by the formula
y = P₀*(1 + r)ˣ
On putting the values , we get
y = 38000*( 1 - 0.15)ˣ
y = 38000*(0.85)ˣ
Therefore , The exponential equation that can model the value of the camper van , in x years is y = 38000*(0.85)ˣ .
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Multiply 2.3 x 4 x 6 and u shall get yer answer.
Answer:
475.
Step-by-step explanation:
We have been given that for a normal distribution with μ=500 and σ=100. We are asked to find the minimum score that is necessary to be in the top 60% of the distribution.
We will use z-score formula and normal distribution table to solve our given problem.

Top 60% means greater than 40%.
Let us find z-score corresponding to normal score to 40% or 0.40.
Using normal distribution table, we got a z-score of
.
Upon substituting our given values in z-score formula, we will get:





Therefore, the minimum score necessary to be in the top 60% of the distribution is 475.
Answer:
3.428571429 or approximately 3.43
Step-by-step explanation:
3/2
= 1.5
7/8
= 0.875
1.5/0.875
= 1.714285714
1.714285714/0.5
= 3.428571429
or approximately 3.43