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stellarik [79]
1 year ago
15

HELPPP i need to find standard form and general form, please help

Mathematics
1 answer:
Rudiy271 year ago
3 0

The equation in slope-intercept form is y = 13/8x -17/8 and the equation in standard form is 13x -8y = 17

<h3>Equation of a line</h3>

A line is the shortest distance between two points. The equation of a line in slope-intercept form is y = mx + b while as a standard notation is Ax+By = C

Given the coordinate points (-3, -7) and (5, 6)

<u>Determine the slope</u>

Slope = 6-(-7)/5-(-3)

Slope = 13/8

<u>For the y-intercept</u>

6 = 13/8(5) + b

6 = 65/8 + b

b = 6 - 65/8

b = -17/8

The equation in slope-intercept form is y = 13/8x -17/8

Write in standard form

Recall y = 13/8x - 17/8

<em>Multiply through by 8</em>

8y = 13x - 17

-13x + 8y = -17

13x -8y = 17

Hence the equation in standard form is 13x -8y = 17

Learn more on equation of a line here: brainly.com/question/13763238

#SPJ1

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What is the sum of the series? 4 ∑k=1 (2k^2−4)
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The sum of the series \sum_{k=1}^{4}\left(2 k^{2}-4\right) is 44.

Step-by-step explanation:

The given series is \sum_{k=1}^{4}\left(2 k^{2}-4\right)=44

To find the sum of the series, we need to substitute the values for k in the series.

\sum_{k=1}^{4}\left(2 k^{2}-4\right)=\left[2(1)^{2}-4\right]+\left[2(2)^{2}-4\right]+\left[2(3)^{2}-4\right]+\left[2(4)^{2}-4\right]

Now, simplifying the square terms, we get,

[2(1)-4]+[2(4)-4]+[2(9)-4]+[2(16)-4]

Multiplying the terms,

[2-4]+[8-4]+[18-4]+[32-4]

Subtracting the values within the bracket term, we get,

-2+4+14+28

Now, adding all the terms, we get the sum of the series,

\sum_{k=1}^{4}\left(2 k^{2}-4\right)=44

Thus, the sum of the series is \sum_{k=1}^{4}\left(2 k^{2}-4\right)=44

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