think of it as half a circle which all equals up to 180 degrees
subtract 180 degrees with 62 degrees which 62 degrees is in the problem.
180-62=118 degrees
so your answer is C) 118 degrees
hope that helped you out:)
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Answer:
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My answer Is The 4th Statement because a positive number is on the other side of the number line as the negative number and if it were just negative 5 and positive 5 it would be correct. I’m just trying the best I can to help you .
Given b equals -3, determine if it is a solution to 4b - 6 = - 18.
So, we have our given which is b = -3, and we are asked to determine if it a solution to the above equation.
To do this, we can plug -3 in for b and see if it works out.
Work:
Plug in -3 for b.
4(-3) - 6 = - 18
-12 - 6 = -18
-12 - 6 = - 18
Thus, b = -3 is a viable solution for the equation of 4b - 6 = -18.
1. Find the derivative of <span>P(x)=3x^3+2x^2-6x. It's P'(x)=9x^2 + 4x - 6.
2. Set this result equal to zero and solve for the critical values:
</span> 9x^2 + 4x - 6 = 0 Using the quadratic formula, I got
x = [-4 plus or minus sqrt(232)] / 18. Reducing this,
x = [-4 plus or minus 2 sqrt(58)]; thus, there are two real, unequal roots and two real, unequal critical values.
3. One at a time, examine the two critical values: determine whether the derivative changes from neg to pos or from pos to neg at each of these values. Example: If the derivative is pos to the left of the first c. v. and neg to the right, we've got a local max.
4. Since there are only 2 critical values, you can have no more than 1 local max (corresponding to a change in the sign of the derivative from pos to neg) and one local min. (from neg to pos).
Message me if this explanation is not sufficient to help you understand this problem thoroughly.
