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enot [183]
3 years ago
6

What is the answer for 9-0-5-(-20)+(-13)?

Mathematics
2 answers:
Nitella [24]3 years ago
4 0

The correct answer is: 11

Here’s how you solve it!

You can remove the 0 since when you add or subtract 0 it stays the same.

Then you would want to look at the first set of parentheses (-20)

Since it is -(-20) this changes the sign to a positive +20

9-5+20+(-13)

Now since the + is in front of the (-13) it remains the same.

Now you are left with this:

9-5+20-13

9-5=4

4+20=24

24-13=11

Then you are left with your answer: 11

Hope this helps! :3

GrogVix [38]3 years ago
4 0
The answer is 11 because 9-5 is 4 and 4 -(-20) is 24 and 23 + (-13) is 11
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200 messages

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2 years ago
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A: {71,73,79,83,87} B:{57,59,61,67}
Jobisdone [24]

Answer:

\frac{3}{5}.

Step-by-step explanation:

We have been given two sets as A: {71,73,79,83,87} B:{57,59,61,67}. We are asked to find the probability that both numbers are prime, if one number is selected at random from set A, and one number is selected at random from set B.

We can see that in set A, there is only one non-prime number that is 87 as it is divisible by 3.

So there are 4 prime number in set A and total numbers are 5.

P(\text{Prime number from A})=\frac{4}{5}

We can see that in set B, there is only one non-prime number that is 57 as it is divisible by 3.

So there are 3 prime number in set B and total numbers are 4.

P(\text{Prime number from B})=\frac{3}{4}

Now, we will multiply both probabilities to find the probability that both numbers are prime. We are multiplying probabilities because both events are independent.

P(\text{Prime number from A and B})=\frac{4}{5}\times \frac{3}{4}

P(\text{Prime number from A and B})=\frac{1}{5}\times \frac{3}{1}

P(\text{Prime number from A and B})=\frac{3}{5}

Therefore, the probability that both numbers are prime would be \frac{3}{5}.

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