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2 years ago

Can you help me please!!!!

Mathematics

2 answers:

valentinak56 [21]2 years ago

6 0

Answer:

Irrational

Step-by-step explanation:

$\sqrt{9}= 3$

3 × √3 = 3√3 which is irrational

Hope this helped and brainliest please

SpyIntel [72]2 years ago

3 0

Product is multiplication:

√3 x √9 = 3√3 = 5.19615....

Because the fraction does not end, it is not rational.

Answer: Irrational

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Prove the following statement.

gayaneshka [121]

Answer:

You can prove this statement as follows:

Step-by-step explanation:

An odd integer is a number of the form $2k+1$ where $k\in \mathbb{Z}$ . Consider the following cases.

Case 1. If $k$ is even we have: $(2k+1)^{2}=(2(2s)+1)^{2}=(4s+1)^{2}=16s^2+8s+1=8(2s^2+s)+1$ .

If we denote by $m=2s^2+2$ we have that $(2k+1)^{2}=8m+1$ .

Case 2. if $k$ is odd we have: $(2k+1)^{2}=(2(2s+1)+1)^{2}=(4s+3)^{2}=16s^2+24s+9=16s^{2}+24s+8+1=8(2s^{2}+3s+1)+1$ .

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This result says that the remainder when we divide the square of any odd integer by 8 is 1.

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

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3 years ago

Read 2 more answers

All it's asking is to solve, I've tried to drop the exponent down but I get stuck

Deffense [45]

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3 years ago

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<, > - dotted line

≤, ≥ - solid line

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3 years ago

Can you help me please!!!!​

Can you help me please!!!!