In each table, x increases by 1. We start with x = 0 and stop with x = 3. So we will focus on the y columns of each table as those are different.
Let's move from left to right along the four tables.
For the first table, we go from y = 1 to y = 2. That's an increase of 1
Sticking with the first table, we go from y = 2 to y = 4. The increase is now 2
Since the increase is not the same, this means the table is not linear. The y increase must be constant. We can rule out choice A
Choice B can be ruled out as well. Why? Because...
the jump from y = 0 to y = 1 is +1
the jump from y = 1 to y = 3 is +2
The same problem comes up as it did with choice A
Choice C has the same problem, but the increase turns into a decrease half the time. We go from y = 0 to y = 1, then we go back to y = 0 so the "increase" is really a decrease. We can think of it as a negative increase. Regardless, this allows us to rule out choice C
Only choice D is the answer. Each time x goes up by 1, y goes up by 2. Therefore the slope is 2/1 = 2
Answer:
Domain (-3,-2,-1,0,1,2)
Range (-2,0,1,2,3)
This is not a function
Step-by-step explanation:
Domain (-3,-2,-1,0,1,2)
Range (-2,0,1,2,3)
one x-value with two y-values, (-1, 2) and (-1, -2)
not a function
Plotting the graph should be easy
left side are x-values
right side are y-values
U will first need to collect the like terms,
x+16>-5x+4
-5x will go to the other side becoming 5x while 16 while also cross the other side becoming -16
x+5x>4 -16
6x> when 4 is taken out from -16 it becomes - 12
6x>-12 when divided the answer obtained will be -2
Answer:
$48
Step-by-step explanation:
if youre paying 9.60 in tax and the tax is 20% you have to find out what 9.60 is 20% of
and 9.60 is 20% of 48
Answer:
Rate of change of the area of the square is 42 units at t = 2.
Step-by-step explanation:
We note that the area of the square is given by: 
but we aim to find 
. But we can use the chain rule to pull out that dA/dt. Doing so gives us:
Now, 
(by the power rule and 
But since we have "x" and not "t", we want to find what x is when t = 2. Substituting t = 2 gives us x(2) = 3(2) + 1 = 7.
So, finally, we see that:
