Strictly speaking, x^2 + 2x + 4 doesn't have solutions; if you want solutions, you must equate <span>x^2 + 2x + 4 to zero:
</span>x^2 + 2x + 4= 0. "Completing the square" seems to be the easiest way to go here:
rewrite x^2 + 2x + 4 as x^2 + 2x + 1^2 - 1^2 = -4, or
(x+1)^2 = -3
or x+1 =i*(plus or minus sqrt(3))
or x = -1 plus or minus i*sqrt(3)
This problem, like any other quadratic equation, has two roots. Note that the fourth possible answer constitutes one part of the two part solution found above.
Answer:
C
Step-by-step explanation:
C is the correct answer because the other 3 points are not correct when you put the numbers into the equation.
y = 16 + 0.5x
20 = 16 + 0.5(8)
20 = 20
Step-by-step explanation:
<u>There is one possible way:</u>
- (4x² - 47x + 141)/(x² + 13x + 40) =
- (4x² + 4*13x + 4*40 - 47x - 52x - 160 + 141)/(x² + 13x + 40) =
- 4 - (99x + 19)/(x² + 13x + 40)
No further simplification
Answer:
I think red
Step-by-step explanation:
SRY i I am wrong
