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3 years ago

3x+3y= 368x-5y=31Help Plz

Mathematics

1 answer:

mr Goodwill [35]3 years ago

7 0

Answer:

{x = 7 ,y = 5

Step-by-step explanation:

Solve the following system:

{3 x + 3 y = 36 | (equation 1)

8 x - 5 y = 31 | (equation 2)

Swap equation 1 with equation 2:

{8 x - 5 y = 31 | (equation 1)

3 x + 3 y = 36 | (equation 2)

Subtract 3/8 × (equation 1) from equation 2:

{8 x - 5 y = 31 | (equation 1)

0 x+(39 y)/8 = 195/8 | (equation 2)

Multiply equation 2 by 8/39:

{8 x - 5 y = 31 | (equation 1)

0 x+y = 5 | (equation 2)

Add 5 × (equation 2) to equation 1:

{8 x+0 y = 56 | (equation 1)

0 x+y = 5 | (equation 2)

Divide equation 1 by 8:

{x+0 y = 7 | (equation 1)

0 x+y = 5 | (equation 2)

Collect results:

Answer: {x = 7 ,y = 5

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