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1 year ago

Can someone solve this

Mathematics

1 answer:

RSB [31]1 year ago

7 0

a) 110°

b) 39°

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I WILL GIVE 30 POINTS TO THOSE WHO FILL IN THE BLANK CORRECTLY

matrenka [14]

Answer:

x=7

Step-by-step explanation:

by pythagoras, 25^2=24^2+x^2

solve for x

6 0

2 years ago

Shani borrowed $5000 at an annual interest rate of 4% compounded yearly. William borrowed the same amount of money at an annual

Natalka [10]

Answer: William will pay $ 330.76 more interest than Shani at the end of 3 years.

Step-by-step explanation:

Compound interest = $P((1+r)^t-1)$ <em> , </em>P= principal , r= rate of interest , t= time

Given: P = $5000 , t= 3 years

For Shani , r= 4% = 0.04

Compound interest = $5000((1+0.04)^3-1)$

$=5000(1.124864-1)\\\\=5000(0.124864)\\\\=\$\ 624.32$

For William, r= 6%= 0.06

Compound interest = $5000((1+0.06)^3-1)$

$=5000(1.191016-1)\\\\=5000(0.191016)\\\\=\$\ 955.08$

Difference = $ ( 955.08- 624.32)

= $ 330.76

Hence, William will pay $ 330.76 more interest than Shani at the end of 3 years.

6 0

3 years ago

X squared plus 8 squared equals 9<br> What is X?

BabaBlast [244]

Answer:

x = $i\sqrt{55} , -i\sqrt{55}$

Step-by-step explanation:

x^2 + 8^2 = 9

Simplify the 8^2

x^2 + 64 = 9

Subtract 64 from both sides

x^2 = -55

Take the square root from both sides

x = +/- $\sqrt{-55}$

Simplify

x = $i\sqrt{55} , -i\sqrt{55}$

Hope this helps!

4 0

2 years ago

Identify the range of the function. A) (2, 8) B) [2, 8] C) (−5, 9) D) [−5, 9]

Ivanshal [37]

Answer:

The answer is "Option A"

Step-by-step explanation:

The domain is the collection of the value, which belongs to the separate variable (horizontal axis). So, to find a region with a graph, it must search for the function, which starts and end. And at all these levels we are searching at x-values.

Its starting point is (2,9) and the ending point is (8,3). Therefore, x= 2 to x=8 is the domain.

5 0

3 years ago

NEED ANSWER

grandymaker [24]

Answer:

$\frac{x^{2}}{144}+\frac{y^{2}}{79.995}=1$

Step-by-step explanation:

An ellipse centered a point (h,k) has the following formula:

$\frac{(x-h)^{2}}{a^{2}}+\frac{(y-k)^{2}}{b^{2}}=1$

The distance between foci is:

$2\cdot c = \sqrt{[8-(-8)]^{2}+(0-0)^{2}}$

$2\cdot c = 16$

$c = 8$

The center of the ellipse is:

$C(x,y) = (-8 + 8, 0 + 0)$

$C(x,y) = (0,0)$

The known vertex is on the horizontal axis of the ellipse. Then, the length of the semi-major axis is:

$a = \sqrt{(12-0)^{2}+(0-0)^{2}}$

$a= 12$

The length of the semi-minor axis is given by the following expression:

$c =\sqrt{a^{2}-b^{2}}$

$b = \sqrt{a^{2}-c^{2}}$

$b = \sqrt{12^{2}-8^{2}}$

$b \approx 8.944$

The equation of the ellipse is:

$\frac{x^{2}}{144}+\frac{y^{2}}{79.995}=1$

5 0

3 years ago