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1 year ago

Factor and solves the polynomial x(to the 2nd power) + 5x + 4 = 0 x= (blank) and x= (blank)

Mathematics

1 answer:

zubka84 [21]1 year ago

3 0

Answer:

$x = -4~ \text{and}~ x = -1$

Step-by-step explanation:

$~~~~~~~x^2 +5x +4 =0\\\\\implies x^2 +4x +x +4 = 0\\\\\implies x(x+4) +(x+4) = 0\\\\\implies (x+4)(x+1) = 0\\\\\implies x = -4,~~ x = -1$

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Find slope intercept form of 5x+8y=120 passing through (4,5)

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Answer:

$y=-(5/8)x+(15/2)$ or $y=-0.625x+7.5$

Step-by-step explanation:

The question is

Find the slope intercept form of the line parallel to the line 5x+8y=120 passing through (4,5)

step 1

Find the slope of the given line

we have

$5x+8y=120$

isolate the variable y

$8y=-5x+120$

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The slope of the given line is m=-5/8

step 2

Find the slope of the line parallel to the given line

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If two lines are parallel, then their slopes are the same

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step 3

Find the equation of the line into slope intercept form

The equation of the line into slope intercept form is equal to

$y=mx+b$

we have

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Question: Find The Sum Of The Integers From -6 To 58 Of Ss. O 1,500 O 1,734 O 1,690 O 1,621

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Answer:

The Sum Of The Integers From -6 To 58 is <u>1690.</u>

Step-by-step explanation:

Given,

$a=-6$

$T_n=58$

We have to find out the sum of integers from -6 To 58.

Firstly we will find out the total number of terms that is 'n'.

Here $a_1=-6\ and\ a_2=-5$

$\therefore d=a_2-a_1=-5-(-6)=-5+6=1$

Now we use the formula of A.P.

$T_n=a+(n-1)d$

On substituting the values, we get;

$58=-6+(n-1)1\\\\n-1=58+6\\\\n-1=64\\\\n=64+1=65$

So there are 65 terms in between -6 To 58.

That means we have to find the sum of 65 terms in between -6 To 58.

Now we use the formula of Sum of n_terms.

$S_n=\frac{n}{2}(2a-(n-1)d)$

On substituting the values, we get;

$S_{65}=\frac{65}{2}(2\times-6+(65-1)1)\\\\S_{65}=\frac{65}{2}(-12+64)\\\\S_{65}=\frac{65}{2}\times52\\\\S_{65}=65\times26=1690$

Hence The Sum Of The Integers From -6 To 58 is <u>1690.</u>

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