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3 years ago

Solve: m/9=2/3 This is for 6th grade math

Mathematics

2 answers:

SSSSS [86.1K]3 years ago

7 0

Answer:

m=6

Step-by-step explanation:

2/3 = 6/9

9 divided by 3 = 3

3 + 3 = 6

therefore your answer is 6

coldgirl [10]3 years ago

4 0

Answer:

m/9=2/3 m=6

Step-by-step explanation:

Because m over 9 is equal to 2 over 3, m = 6. Since 9 is equal to 3 times 3, you have to multiply 2 times 3. You multiply because whatever you do to 1 number of the fraction, you do to the other.

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For which of the following compound inequalities is there no solution?

Bess [88]

Answer:

(a) $6m \le - 36$ and $m + 24 > 20$

Step-by-step explanation:

Required

Which of a to d has no solution

(a) $6m \le - 36$ and $m + 24 > 20$

We have: $m + 24 > 20$

Sole for m

$m >20 - 24$

$m >-4$

$6m \le - 36$

Divide by 6

$m \le -6$

So, we have:

$m \le -6$ and $m >-4$

$m \le -6$ implies that: m = -6,-7,-8,-9.....

$m >-4$ implies that m = -3,-2,-1,0.....

<em>Hence, there is no solution</em>

8 0

2 years ago

What are the two smallest consecutive odd integers whose sum is greater than 17

Mice21 [21]

Answer:

9 and 11

Step-by-step explanation:

5 0

2 years ago

Pyramids and cones have how many base

Blababa [14]

Answer:

pyramids and cones have 1 base.

Step-by-step explanation:

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2 years ago

Hello can someone help me simplify 4) and 5)? Thank you and please include steps :)

Leni [432]

Alrighty

remember some rules
$(ab)^c=(a^c)(b^c)$
and
$x^{-m}=\frac{1}{x^m}$
and
$x^0=1$ for all real values of x
and
$(a^b)^c=a^{bc}$
and
$(\frac{a}{b})^c=\frac{a^c}{b^c}$
and
(a/b)/(c/d)=(ad)/(bc)
and
$(a^b)(a^c)=a^{b+c}$
and
$\frac{a^m}{a^n}=a^{m-n}$
and don't forget pemdas
example: $-x^m=-1(x^m)$ but $(-x)^m=(-1)^m(x^m)$

so

4.
$(\frac{c^{-2}}{2})^{-2}=$

$\frac{(c^{-2})^{-2}}{2^{-2}}=$

$\frac{c^4}{\frac{1}{2^2}}=$

$\frac{c^4}{\frac{1}{4}}=$

$4c^4$

5.

$\frac{(-a)^4bc^5}{-a^2b^{-3}c^0}=$

$\frac{(-1)^4(a)^4bc^5}{-1(a^2)(\frac{1}{b^3}(1)}=$

$\frac{(1)a^4bc^5}{\frac{(-1)(a^2)}{b^3}}=$

$\frac{(a^4bc^5)b^3}{(-1)(a^2)}=$

$\frac{-a^4b^4c^5}{a^2}=$

$-a^2b^4c^5$