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IceJOKER [234]
2 years ago
14

Elaina Kicks A Soccer Ball With An Initial Velocity Of

Mathematics
1 answer:
VladimirAG [237]2 years ago
5 0

By using the motion equations, we conclude that she will make the goal.

<h3>Will she make the goal?</h3>

First, we know that the goal is 20ft away, and the position in x is given by:

x = 28*cos(58)*t

Let's find the time in which the ball will travel these 20 ft.

20 =  28*cos(58)*t

(20)/(28*cos(58)) = t = 1.35

So the horizontal distance is covered in 1.35 seconds, now let's see which is the height of the ball at that time.

The height equation is:

y = -16*t^2 +28*sin(58)*t

Evaluating in t = 1.35 we get:

y = -16*(1.35)^2 +28*sin(58)*1.35\\\\y = 2.9

And the goal is 5ft tall, so we can conclude that she will make the goal.

If you want to learn more about motion equations:

brainly.com/question/19365526

#SPJ1

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Step-by-step explanation:

The value of the velocity v is given as:

v = \frac{ds}{dt} = 6 sin(2t) m/s

To find s, we have to integrate and apply the initial values of s = o when t = 0:

\frac{ds}{dt} = 6 sin(2t)\\\\\int\limits^s_0 {ds} = \int\limits^t_0 {6sin(2t)} \, dt\\\\s|^s_o = -3cos(2t)|^t_o\\\\s - 0 = -3cos(2t) -(-3cos(0))\\\\s = -3cos(2t) + 3(1)\\\\s = -3cos(2t) + 3

When t = π/2, s will be:

s = -3cos(2 * π/2) + 3

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s = -3(-1) + 3

s = 3 + 3

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4 0
3 years ago
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1. 25
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The diagonals of a rhombus are 21 m and 32 m. What is the area of the rhombus?<br> 30 POINTS
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I have included attachment below

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answer is 336 m^2

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