By using the motion equations, we conclude that she will make the goal.
<h3>
Will she make the goal?</h3>
First, we know that the goal is 20ft away, and the position in x is given by:
![x = 28*cos(58)*t](https://tex.z-dn.net/?f=x%20%3D%2028%2Acos%2858%29%2At)
Let's find the time in which the ball will travel these 20 ft.
![20 = 28*cos(58)*t](https://tex.z-dn.net/?f=20%20%3D%20%2028%2Acos%2858%29%2At)
![(20)/(28*cos(58)) = t = 1.35](https://tex.z-dn.net/?f=%2820%29%2F%2828%2Acos%2858%29%29%20%3D%20t%20%3D%201.35)
So the horizontal distance is covered in 1.35 seconds, now let's see which is the height of the ball at that time.
The height equation is:
![y = -16*t^2 +28*sin(58)*t](https://tex.z-dn.net/?f=y%20%3D%20-16%2At%5E2%20%2B28%2Asin%2858%29%2At)
Evaluating in t = 1.35 we get:
![y = -16*(1.35)^2 +28*sin(58)*1.35\\\\y = 2.9](https://tex.z-dn.net/?f=y%20%3D%20-16%2A%281.35%29%5E2%20%2B28%2Asin%2858%29%2A1.35%5C%5C%5C%5Cy%20%3D%202.9)
And the goal is 5ft tall, so we can conclude that she will make the goal.
If you want to learn more about motion equations:
brainly.com/question/19365526
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