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3 years ago

Can someone help on this using the pythagorean theorem

Mathematics

2 answers:

viva [34]3 years ago

6 0

Answer: 337 or 337^2 ~ 142129

Hope this helps :)

hodyreva [135]3 years ago

4 0

Answer:

a= 11.62

Step-by-step explanation:

a=sq rt of c^2 - b^2

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At boarding school, students spend 1/4 of their time eating and sleeping, 3/5 of their time in class, and 1'12 studying. The res

steposvetlana [31]

Answer:

1/15 of their time is free time.

Step-by-step explanation:

To find the answer to this 2-step problem, we have to add all the fractions up, then find how much of that time is not part of the fraction.

So to add all the fractions, you have the equation:

1/4 + 3/5 + 1/12

The first thing we have to do is to find a common denominator.

4, 5, and 12 are each able to multiply into 60.

So we can make the equation now with a common denominator.

15/60+36/60+5/60=56/60.

We now can simplfy this.

56/60=14/15

Now that we know how long it is to do all the other activities, it tells us that the rest of the time is free time. To find the rest of the time, we have to do:

1-14/15=1/15

So 1/15 of their time is free time.

8 0

3 years ago

plz help i need this so bad i will give brainlyest There are 9 dogwood trees currently in the park. Park workers will plant 8 mo

Svet_ta [14]

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3 0

3 years ago

Read 2 more answers

Work out the area of abcd. please ensure you give workings out too.

ipn [44]

Answer:

$\displaystyle A_{\text{Total}}\approx45.0861\approx45.1$

Step-by-step explanation:

We can use the trigonometric formula for the area of a triangle:

$\displaystyle A=\frac{1}{2}ab\sin(C)$

Where a and b are the side lengths, and C is the angle between the two side lengths.

As demonstrated by the line, ABCD is the sum of the areas of two triangles: a right triangle ABD and a scalene triangle CDB.

We will determine the area of each triangle individually and then sum their values.

Right Triangle ABD:

We can use the above area formula if we know the angle between two sides.

Looking at our triangle, we know that ∠ADB is 55 DB is 10.

So, if we can find AD, we can apply the formula.

Notice that AD is the adjacent side to ∠ADB. Also, DB is the hypotenuse.

Since this is a right triangle, we can utilize the trig ratios.

In this case, we will use cosine. Remember that cosine is the ratio of the adjacent side to the hypotenuse.

Therefore:

$\displaystyle \cos(55)=\frac{AD}{10}$

Solve for AD:

$AD=10\cos(55)$

Now, we can use the formula. We have:

$\displaystyle A=\frac{1}{2}ab\sin(C)$

Substituting AD for a, 10 for b, and 55 for C, we get:

$\displaystyle A=\frac{1}{2}(10\cos(55))(10)\sin(55)$

Simplify. Therefore, the area of the right triangle is:

$A=50\cos(55)\sin(55)$

We will not evaluate this, as we do not want inaccuracies in our final answer.

Scalene Triangle CDB:

We will use the same tactic as above.

We see that if we can determine CD, we can use our area formula.

First, we can determine ∠C. Since the interior angles sum to 180 in a triangle, this means that:

$\begin{aligned}m \angle C+44+38&=180 \\m\angle C+82&=180 \\ m\angle C&=98\end{aligned}$

Notice that we know the angle opposite to CD.

And, ∠C is opposite to BD, which measures 10.

Therefore, we can use the Law of Sines to determine CD:

$\displaystyle \frac{\sin(A)}{a}=\frac{\sin(B)}{b}$

Where A and B are the angles opposite to its respective sides.

So, we can substitute 98 for A, 10 for a, 38 for B, and CD for b. Therefore:

$\displaystyle \frac{\sin(98)}{10}=\frac{\sin(38)}{CD}$

Solve for CD. Cross-multiply:

$CD\sin(98)=10\sin(38)$

Divide both sides by sin(98). Hence:

$\displaystyle CD=\frac{10\sin(38)}{\sin(98)}$

Therefore, we can now use our area formula:

$\displaystyle A=\frac{1}{2}ab\sin(C)$

We will substitute 10 for a, CD for b, and 44 for C. Hence:

$\displaystyle A=\frac{1}{2}(10)(\frac{10\sin(38)}{\sin(98)})\sin(44)$

Simplify. So, the area of the scalene triangle is:

$\displaystyle A=\frac{50\sin(38)\sin(44)}{\sin(98)}$

Therefore, our total area will be given by:

$\displaystyle A_{\text{Total}}=50\cos(55)\sin(55)+\frac{50\sin(38)\sin(44)}{\sin(98)}$

Approximate. Use a calculator. Thus:

$\displaystyle A_{\text{Total}}\approx45.0861\approx45.1$

8 0

3 years ago

* Simplify the expression: (-6p+7). -4

Art [367]

Answer:

I'm assuming you need to distribute. When simplified the expression is 42p-28

Step-by-step explanation:

7 0

2 years ago

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Solve for x A 15 B 16 C 2.4 D 12

Ne4ueva [31]

Answer: bd=8 dc=2 and ae=4 so value of ab=16

Step-by-step explanation:

7 0

2 years ago