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nataly862011 [7]

2 years ago

10

PLEASE HELP ! Suppose another company offers a special

1 answer:

kolezko [41]2 years ago

5 0

The special is cheaper than Bella's price. Then the correct option is B.

<h3>What is the linear system?</h3>

A linear system is one in which the parameter in the equation has a degree of one. It might have one, two, or even more variables.

Suppose another company offers a special banquet price of $4,000 for 150 people.

Then the special is cheaper than Bella's price.

Then the correct option is B.

More about the linear system link is given below.

brainly.com/question/20379472

#SPJ1

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o-na [289]

The answer is : square root of 14 is between 3 and 4
√14= 3.74

4 0

3 years ago

Read 2 more answers

If f(x) is a linear function, f(−2)=4, and f(1)=−1, find an equation for f(x)

juin [17]

Answer:

$y = -\frac{5}{3}x+\frac{2}{3}$

Step-by-step explanation:

Given

$f(-2) = 4$

$f(1) = -1$

Required

The equation of the function

The given parameters means that:

$(x_1,y_1) = (-2,4)$

$(x_2,y_2) = (1,-1)$

Calculate the slope (m)

$m = \frac{y_2 -y_1}{x_2 -x_1}$

$m = \frac{-1-4}{1--2}$

$m = \frac{-5}{3}$

The equation is then calculated using:

$y = m(x - x_1) + y_1$

This gives:

$y =\frac{-5}{3}(x--2)+4$

$y =\frac{-5}{3}(x+2)+4$

Open bracket

$y = -\frac{5}{3}x-\frac{10}{3}+4$

Take LCM

$y = -\frac{5}{3}x+\frac{-10+12}{3}$

$y = -\frac{5}{3}x+\frac{2}{3}$

6 0

3 years ago

strojnjashka [21]

Answer:

The candle has a radius of 8 centimeters and 16 centimeters and uses an amount of approximately 1206.372 square centimeters.

Step-by-step explanation:

The volume ( $V$ ), in cubic centimeters, and surface area ( $A_{s}$ ), in square centimeters, formulas for the candle are described below:

$V = \pi\cdot r^{2}\cdot h$ (1)

$A_{s} = 2\pi\cdot r^{2} + 2\pi\cdot r \cdot h$ (2)

Where:

$r$ - Radius, in centimeters.

$h$ - Height, in centimeters.

By (1) we have an expression of the height in terms of the volume and the radius of the candle:

$h = \frac{V}{\pi\cdot r^{2}}$

By substitution in (2) we get the following formula:

$A_{s} = 2\pi \cdot r^{2} + 2\pi\cdot r\cdot \left(\frac{V}{\pi\cdot r^{2}} \right)$

$A_{s} = 2\pi \cdot r^{2} +\frac{2\cdot V}{r}$

Then, we derive the formulas for the First and Second Derivative Tests:

First Derivative Test

$4\pi\cdot r -\frac{2\cdot V}{r^{2}} = 0$

$4\pi\cdot r^{3} - 2\cdot V = 0$

$2\pi\cdot r^{3} = V$

$r = \sqrt[3]{\frac{V}{2\pi} }$

There is just one result, since volume is a positive variable.

Second Derivative Test

$A_{s}'' = 4\pi + \frac{4\cdot V}{r^{3}}$

If $\left(r = \sqrt[3]{\frac{V}{2\pi}}\right)$ :

$A_{s} = 4\pi + \frac{4\cdot V}{\frac{V}{2\pi} }$

$A_{s} = 12\pi$ (which means that the critical value leads to a minimum)

If we know that $V = 3217\,cm^{3}$ , then the dimensions for the minimum amount of plastic are:

$r = \sqrt[3]{\frac{V}{2\pi} }$

$r = \sqrt[3]{\frac{3217\,cm^{3}}{2\pi}}$

$r = 8\,cm$

$h = \frac{V}{\pi\cdot r^{2}}$

$h = \frac{3217\,cm^{3}}{\pi\cdot (8\,cm)^{2}}$

$h = 16\,cm$

And the amount of plastic needed to cover the outside of the candle for packaging is:

$A_{s} = 2\pi\cdot r^{2} + 2\pi\cdot r \cdot h$

$A_{s} = 2\pi\cdot (8\,cm)^{2} + 2\pi\cdot (8\,cm)\cdot (16\,cm)$

$A_{s} \approx 1206.372\,cm^{2}$

The candle has a radius of 8 centimeters and 16 centimeters and uses an amount of approximately 1206.372 square centimeters.

3 0

3 years ago

Erin had 55 stuffed bears. She took out her 7 favorite and equally divided the rest among her 3 sisters. How many bears did each

m_a_m_a [10]

Answer:

16

Step-by-step explanation:

55-7= 48

48/3 = 16

5 0

2 years ago

Slope of (10,8) (2,1)

Reptile [31]

Answer:

slope=7/8

Step-by-step explanation:

8-1/10-2= 7/8

6 0

3 years ago