Plastic cups come in packages of 24 and straws come in packages of 20, whats the smallest number of each that could be bought so
that you had the same amount of cups and straws? 200 240 120 480
1 answer:
Answer:
120
Step-by-step explanation:
No. of plastic cups = 24
No. of straws =20
We need to find the smallest number of each that could be bought so that you had the same amount of cups and straws.
Prime factrisation of 24 = 2×3×2×2
Prime factorisation of 20 = 2×5×2
LCM = 120
Hence, the smallest number of each type will be 120.
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Answer:
408 neighbours, 7 each
Step-by-step explanation:
2856 is divisible by 7
So each gets 7
Neighbours: 2856/7 = 408
A. 3^n 3^20
b.N^n N^20
c.12^n 12^9
d.237^n 237^4
Answer:
option C is correct answer
Answer:
40%
Step-by-step explanation:
12 ÷ 20 = .6
You can convert the .6 to a percentage by multiplying it:
.6 x 100 = 60%
If 12 is 60% of 20, then that means 40% was taken away.
Answer:
r = 11
L = 6
Step-by-step explanation:
7(6) = 42
5(11) = 55
42 + 55 = 97
