Your number can be none other than 89 .
Make one side equal zero
minus 11 to both sides
x^2-6x-2=0
another quadratic equation
if you hahve
ax^2+bx+c=0
x=

1x^2-6x-2=0
a=1
b=-6
c=-2
x=

x=

x=

x=

x=

x=

or

aprox
x=6.31662 or -0.316625
Answer:
V=25088π vu
Step-by-step explanation:
Because the curves are a function of "y" it is decided to take the axis of rotation as y
, according to the graph 1 the cutoff points of f(y)₁ and f(y)₂ are ±2
f(y)₁ = 7y²-28; f(y)₂=28-7y²
y=0; x=28-0 ⇒ x=28
x=0; 0 = 7y²-28 ⇒ 7y²=28 ⇒ y²= 28/7 =4 ⇒ y=√4 =±2
Knowing that the volume of a solid of revolution V=πR²h, where R²=(r₁-r₂) and h=dy then:
dV=π(7y²-28-(28-7y²))²dy ⇒dV=π(7y²-28-28+7y²)²dy = 4π(7y²-28)²dy
dV=4π(49y⁴-392y²+784)dy integrating on both sides
∫dV=4π∫(49y⁴-392y²+784)dy ⇒ solving ∫(49y⁴-392y²+784)dy
49∫y⁴dy-392∫y²dy+784∫dy =
V=4π(
) evaluated -2≤y≤2, or 2(0≤y≤2), also
⇒ V=25088π vu
Answer:
True: If you add 6 to a, this will be greater than b.
Step-by-step explanation:
If the ordered pair (a,b) satisfies the inequality y < x + 6, then the coordinates of this point satisfy the inequality. Substitute into the inequality x = a and y =b:

Check all options:
A. Subtract 6 from b:

So, if you subtract 6 from b it will be less than a but never equal to a, so this option is false.
B.

So, a is greater than b - 6, not b. This option is false.
C. If you add 6 to a, then

This option is true.
D. a+6 is greater than b, so it cannot be less than b. This option is false.