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3 years ago

What is helpful Problem-solving

1 answer:

6 0

Helpful problem solving is handling all problems the same , weather big , small or complex you should always problem solve in a fair way that’s convenient to everyone’s needs

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Which number is the greatest?<br> O 1.2<br> O 1.3<br> O 1.235<br> O 1.003

Vaselesa [24]

Answer:

Option 2 because in decimals, 1.3 will be the largest being that it is followed by the #3. (1.3)

Hope it helped!

8 0

3 years ago

A company has 875 employees. "Half - Price Wednesday," 64% of the employees eat lunch at the company cafeteria. How many employe

Vika [28.1K]

875 × .64= 560

answer: 560 employees eat lunch at the cafeteria on Wednesday.

4 0

3 years ago

Read 2 more answers

Factor x^2+6x-16 into the form (x+a)(x-b), what is a and b?

vfiekz [6]

Answer:

a=-8 b=2

Step-by-step explanation:

x^2+6x-16

x^2+(8-2)x-16=0

x^2+8x-2x-16=0

X(X+8)-2(X+8)=0

(X+8)(x-2)=0

Compare with (X+a)(X+b)

Where we get a=-8 b=2

8 0

3 years ago

What is the slope of this graph? −14 4 14 −4 Number graph ranging from negative 10 to 10 on both the x and y axis. A line passes

spin [16.1K]

The slope of this graph is - 4

Step-by-step explanation:

The slope of a line is $m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$ , where

$(x_{1},y_{1})$ and $(x_{2},y_{2})$ are two points on the line
The slope of a horizontal line is zero
The slope of a vertical line is undefined

∵ The graph is a line

∵ The line passes through points (1 , -2) and (0 , 2)

∴ $x_{1}$ = 1 and $x_{2}$ = 0

∴ $y_{1}$ = -2 and $y_{2}$ = 2

- Substitute these values in the rule below

∵ $m=\frac{y_{2}-y_{1}}{x_{2}-x_{2}}$

∴ $m=\frac{2--2}{0-1}=\frac{4}{-1}$

∴ m = - 4

The slope of this graph is - 4

Learn more:

You can learn more about the slope of a line in brainly.com/question/4152194

#LearnwithBrainly

7 0

3 years ago

Read 2 more answers

A stone is thrown vertically upward from a platform that is 20 feet height at a rate of 160 ft/sec. Use the quadratic function h

Nutka1998 [239]

Check the picture below.

$\textit{vertex of a vertical parabola, using coefficients} \\\\ y=\stackrel{\stackrel{a}{\downarrow }}{-16}x^2\stackrel{\stackrel{b}{\downarrow }}{+160}x\stackrel{\stackrel{c}{\downarrow }}{+20} \qquad \qquad \left(-\cfrac{ b}{2 a}~~~~ ,~~~~ c-\cfrac{ b^2}{4 a}\right)$

$\left(-\cfrac{ 160}{2(-16)}~~~~ ,~~~~ 20-\cfrac{ (160)^2}{4(-16)}\right) \implies \left( - \cfrac{ 160 }{ -32 }~~,~~20 - \cfrac{ 25600 }{ -64 } \right) \\\\\\ \left( 5 ~~~~ ,~~~~ 20 +400 \right)\implies (\stackrel{seconds}{5}~~,~~\stackrel{feet}{420})$

6 0

1 year ago