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1 year ago

A 68° B 32° D 77 11x - 33 [?] с Help Resour Skip

Mathematics

1 answer:

kari74 [83]1 year ago

5 0

Quadrilaterals are shapes with 4 sides. The correct inequality expression is x < 11

<h3>What are quadrilaterals?</h3>

Quadrilaterals are shapes with 4 sides. The given figure is a quadrilateral. The side opposite to 68 degrees is greater than the side opposite 32 degrees to have the equation;

11x - 33 < 77

Add 33 to both sides

11x - 33 + 33 < 77 + 33

11x <110

x < 110/10

x< 11

Hence the correct inequality expression is x < 11

Learn more on inequality here: brainly.com/question/24372553

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V²=u²+2as make u as the subject <br><br>

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Answer:

u as the subject of the given formula is, $u = \sqrt{v^{2}-2as }$

Step-by-step explanation:

Given;

v² = u²+2as

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v² = u²+2as

v² - 2as = u²

take the square - root of both sides of the equation;

$\sqrt{u^{2} } = \sqrt{v^{2}-2as } \\\\u = \sqrt{v^{2}-2as }$

Thus, u as the subject of the given formula is, $u = \sqrt{v^{2}-2as }$

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3 years ago

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Answer:

As the lines are not intersecting nor parallel, they must be skew.

Step-by-step explanation:

Question is incomplete, we consider the nearest match available online.

Parametric equations of two lines are:

L₁ : x=4t+2 , y = 3 , z =-t+1

L₂: x=2s+2 , y= 2s+5 , z = s+1

If lines are parallel then parametric coordinates must be equal scalar multiple of each other which s not true here.

$4t+2=2s+2 ---(1)\\ \\3=2s+5---(2) \\\\-t+1=s+1---(3)$

If lines are intersecting then parametric coordinates must be equal for some value of t and s.

$From (3)\\-t=s\\From (2)\\\\s=\frac{3-5}{2}\\\\s=-1\\\implies t=1\\\\To\,\,check\,\, the \,\,values \,\,of \,\,s\,\, and \,\,t \,\,for\,\,intersection\,\,put \,\,them\,\, in\,\, (1)\\\\4(1)+2= 2(-1)+2\\ 6\ne0$

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