How many 1/5 cup servings are in 3/4 of a cup of ice cream

Members of the student concil are conducting a fundraiser by selling school calendars. After selling 80 calendars, they had a lo

Oksana_A [137]

Answer:

a) $y=8x-1000$

b) $profit=\$8$

c) They'd have lost $1000 if they had sold no calendars.

Step-by-step explanation:

a) The equation of the line in Slope-Intercept form is:

$y=mx+b$

Where "m" is the slope and "b" is the y-intercept.

In this case we know that "y" represents the profit of loss and "x" the number of calendars sold.

Then, according to the exercise, the line passes through these two points:

$(80,-360)$ and $(200,600)$

Then, we can find the slope of the line with the formula $m=\frac{y_2-y_1}{x_2-x_1}$

$m=\frac{-360-600}{80-200}=8$

Now, we can substitute the slope and one of those points into $y=mx+b$ and solve for "b":

$600=8(200)+b\\\\b=-1000$

Then, subtituting values, we get that the equation that describes the relation between the profit of loss and the number of calendars sold, is:

$y=8x-1000$

b) The slope of the line is the profit they made from selling each calendar

$profit=8$

c) The y-intercept is the amount they would have lost if they had sold no calendars:

$b=-1000$

They'd have lost $1000 if they had sold no calendars.

6 0

2 years ago

PLEASE HELP!! 20 POINTS!<br> - ✓ 81+ ✓–49 + ✓ 25+ ✓-1

laiz [17]

Answer:

Step-by-step explanation:

=-9+7i+5+i

=-4+8i

5 0

2 years ago

Read 2 more answers

1.56 times 48 equals

Crank

Answer:

It equals 74.88

Step-by-step explanation:

U jus multiply them

5 0

2 years ago

Read 2 more answers

A researcher selects all of the possible samples with n = 8 scores from a population and computes the mean, dividing by n, for e

Nadusha1986 [10]

Answer:

By the Central Limit Theorem, the average value for all of the sample means is 14.

Step-by-step explanation:

We use the central limit theorem to solve this question.

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sample means of size n can be approximated to a normal distribution with mean $\mu$ and standard deviation, which is also called standard error $s = \frac{\sigma}{\sqrt{n}}$

If the population mean is μ = 14, then what is the average value for all of the sample means?

By the Central Limit Theorem, the average value for all of the sample means is 14.

3 0

3 years ago

H(j + i) - k5 + h<br> when h = 3, i = 4, j = 2, and k = 1<br> pls put how you did it

VikaD [51]

Answer:

16

Step-by-step explanation:

First you want to plug in all the numbers where the letters are

h ( j + i )- k(5) + h

3 ( 2 + 4 )- 1(5) + 3

After this step you will have to distribute the 3 outside the parenthesis. Which you do by multiplying everything in side the parenthesis by the outside number which is three.

6 + 12 - 1(5) + 3

Then you just follow PEMDAS to solve for the rest

6 + 12 - 5 + 3

18 - 5 + 3

13 + 3

16

6 0

2 years ago