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lord [1]
3 years ago
12

Hugo is 6 feet 4 inches tall, weighs 225 pounds, and very muscular. if you think hugo is more likely to be a professional footba

ll player rather than a professional ballroom dancer, you are using:
Mathematics
2 answers:
Anna [14]3 years ago
8 0
I am using an <span>inductive argument. In logical, in this type of argument if the premises are assumed true, it is </span>likely<span> that the conclusion is true (though the conclusion could be false). 

</span><span>An inductive argument is intended to show that its conclusion is probably or likely true, though not certainly true, if its premises all are true. The author of an inductive argument (if sincere) only aims to establish the intended conclusion with a high degree of probability although not with complete certainty.

</span><span>Words such as “probably,” “likely,” and “it is reasonable to conclude” suggest that you intend your argument to show that the conclusion is probably, but not certainly, true. The statement above use the words "more likely", then this word tell us that this is, in fact, an inductive argument.</span>


sergij07 [2.7K]3 years ago
7 0

the answer is that u are using an inductive argument.

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A cylinder has a radius of 3 cm and a height of 4cm. what formula would be used to find the volume
mixas84 [53]

Answer:

required formula: πr^2h

Solution

Formula to find volume of cylinder= πr^2h

= 22/7 ×3×3×4

= 113.14cm^3

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2 years ago
Please help me :(
stiv31 [10]

Answer:

Step-by-step explanation:

Cos \ D = \dfrac{adjacent \ side \ of angle \ D}{hypotenuse}\\\\\\ Cos \ D = \dfrac{72}{75}\\\\\\Cos D = \dfrac{24}{25}

5 0
3 years ago
Cable Strength: A group of engineers developed a new design for a steel cable. They need to estimate the amount of weight the ca
KatRina [158]

Answer:

95% confidence interval for the mean breaking strength of the new steel cable is [763.65 lb , 772.75 lb].

Step-by-step explanation:

We are given that the engineers take a random sample of 45 cables and apply weights to each of them until they break. The mean breaking weight for the 45 cables is 768.2 lb. The standard deviation of the breaking weight for the sample is 15.1 lb.

Since, in the question it is not specified that how much confidence interval has be constructed; so we assume to be constructing of 95% confidence interval.

Firstly, the Pivotal quantity for 95% confidence interval for the population mean is given by;

                            P.Q. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean breaking weight = 768.2 lb

            s = sample standard deviation = 15.1 lb

            n = sample of cables = 45

            \mu = population mean breaking strength

Here for constructing 95% confidence interval we have used One-sample t test statistics as we don't know about population standard deviation.

<u>So, 95% confidence interval for the population mean, </u>\mu<u> is ;</u>

P(-2.02 < t_4_4 < 2.02) = 0.95  {As the critical value of t at 44 degree

                                           of freedom are -2.02 & 2.02 with P = 2.5%}  

P(-2.02 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 2.02) = 0.95

P( -2.02 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 2.02 \times {\frac{s}{\sqrt{n} } } ) = 0.95

P( \bar X-2.02 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+2.02 \times {\frac{s}{\sqrt{n} } } ) = 0.95

<u>95% confidence interval for</u> \mu = [ \bar X-2.02 \times {\frac{s}{\sqrt{n} } } , \bar X+2.02 \times {\frac{s}{\sqrt{n} } } ]

                                     = [ 768.2-2.02 \times {\frac{15.1}{\sqrt{45} } } , 768.2+2.02 \times {\frac{15.1}{\sqrt{45} } } ]

                                     = [763.65 lb , 772.75 lb]

Therefore, 95% confidence interval for the mean breaking strength of the new steel cable is [763.65 lb , 772.75 lb].

3 0
4 years ago
A bag contains 5 blue marbles, 2 blavk marbles, and 3 red marbles. A marble is randomly drawn from the bag. The probability of n
saveliy_v [14]

Answer:

20% black marble 30% red marble

8 0
4 years ago
If the length of AC equals 50, what is the length of the midsegment DE?
balu736 [363]

Answer:

25

Step-by-step explanation:

The mid-segment of the triangle is always parallel to the base and is half the length of the base

3 0
3 years ago
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