Answer:Your left hand side evaluates to:
m+(−1)mn+(−1)m+(−1)mnp
and your right hand side evaluates to:
m+(−1)mn+(−1)m+np
After eliminating the common terms:
m+(−1)mn from both sides, we are left with showing:
(−1)m+(−1)mnp=(−1)m+np
If p=0, both sides are clearly equal, so assume p≠0, and we can (by cancellation) simply prove:
(−1)(−1)mn=(−1)n.
It should be clear that if m is even, we have equality (both sides are (−1)n), so we are down to the case where m is odd. In this case:
(−1)(−1)mn=(−1)−n=1(−1)n
Multiplying both sides by (−1)n then yields:
1=(−1)2n=[(−1)n]2 which is always true, no matter what n is
Answer:
107r³
Step-by-step explanation:
Dkdnksskmsmsmsmsmsmsmsmsms D)
Answer:
2x+5
Step-by-step explanation:
Okay so lets first factor 2x^2+15x+25
2*25=50
10+5=15
10*5=15
(x+10/2)(x+5/2)
=(x+5)(2x+5)
we know that the width is x+5 so that means the length has to be 2x+5
