Answer:
2 3,4,8,90,1,6,7,0,
Step-by-step explanation:
iirbbfolwolwikkekke
Answer:
5
Step-by-step explanation:
253/50 is 5.06
Answer:
(A) 30x+90=300
(B) $7
Step-by-step explanation:
Let x be the roller skating rink's entrance fee for one student.
So, the entrance fee for 30 students=30x
As each student pays a $3 fee to rent skates
So, the fee for rent paid by 30 students= $3x30=$90
The total cost for the students to enter the rink and rent skates= 30x+90
As given that total fee to enter the rink and rent skates is $300.
Therefore, 30x+90=300
(A) The required equation is 30x+90=300.
(B) On solving the equation, we have
![30x+90=300\\\\ \Rightarrow 30x=300-90 \\\\\Rightarrow 30x=210 \\\\\Rightarrow x=210/30 \\\\\Rightarrow x=7](https://tex.z-dn.net/?f=30x%2B90%3D300%5C%5C%5C%5C%20%5CRightarrow%2030x%3D300-90%20%5C%5C%5C%5C%5CRightarrow%2030x%3D210%20%5C%5C%5C%5C%5CRightarrow%20x%3D210%2F30%20%5C%5C%5C%5C%5CRightarrow%20x%3D7)
Hence, the roller skating rink's entrance fee is $7.
1) We calculate the volume of a metal bar (without the hole).
volume=area of hexagon x length
area of hexagon=(3√3 Side²)/2=(3√3(60 cm)²) / 2=9353.07 cm²
9353.07 cm²=9353.07 cm²(1 m² / 10000 cm²)=0.935 m²
Volume=(0.935 m²)(2 m)=1.871 m³
2) we calculate the volume of the parallelepiped
Volume of a parallelepiped= area of the section x length
area of the section=side²=(40 cm)²=1600 cm²
1600 cm²=(1600 cm²)(1 m² / 10000 cm²=0.16 m²
Volume of a parallelepiped=(0.16 m²)(2 m)=0.32 m³
3) we calculate the volume of a metal hollow bar:
volume of a metal hollow bar=volume of a metal bar - volume of a parallelepiped
Volume of a metal hollow bar=1.871 m³ - 0.32 m³=1.551 m³
4) we calculate the mass of the metal bar
density=mass/ volume ⇒ mass=density *volume
Data:
density=8.10³ kg/m³
volume=1.551 m³
mass=(8x10³ Kg/m³ )12. * (1.551 m³)=12.408x10³ Kg
answer: The mas of the metal bar is 12.408x10³ kg or 12408 kg