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2 years ago

8.

1 answer:

8 0

Camila's data set has the greatest interquartile range and the value of IQR = 8 option third is correct.

<h3>What is the range?</h3>

It is defined as the difference between the maximum value in the data set to the minimum value in the data set.

We have:

The amount of money in tips earned by four restaurant servers waiting on 10 tables is represented by the following data sets:

Alyssa {3, 6, 2, 8, 12, 14, 5, 7, 7, 8}

Bryant {9, 2, 7, 50, 0, 5, 2, 8, 6, 8}

Camila {1, 9, 10, 3, 0, 12, 10, 9, 8, 2}

Devon {4, 2, 8, 15, 20, 7, 5, 0, 6, 2}

The IQR for Alyssa:

IQR = Q3 - Q1

IQR = 8 - 5 = 3

The IQR for Bryant:

IQR = Q3 - Q1

IQR = 8 - 2 = 6

The IQR for Camila:

IQR = Q3 - Q1

IQR = 10 - 2 = 8

The IQR for Devon:

IQR = Q3 - Q1

IQR = 8 - 2 = 6

Thus, Camila's data set has the greatest interquartile range and the value of IQR = 8 option third is correct.

Learn more about the range here:

brainly.com/question/17553524

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Quincy sold three times as many magazines as Olivia. Trenton sold two less than twice the number of magazines that Quincy sold.

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Olivia sold 14 magazines.

Step-by-step explanation:

Total magazines sold = 138

Let,

Magazines sold by Olivia = x

Magazines sold by Quincy = y

Magazines sold by Trenton = z

According to given statements;

x+y+z=138 Eqn 1

Quincy sold three times as many magazines as Olivia.

y = 3x Eqn 2

Trenton sold two less than twice the number of magazines that Quincy sold.

z = 2y-2 Eqn 3

Putting value of y from Eqn 2;

$z=2(3x)-2\\z=6x-2\ \ \ \ Eqn\ 4$

Putting value of y from Eqn 2 and value of z from Eqn 3 in Eqn 1

$x+3x+(6x-2)=138\\4x+6x-2=138\\10x=138+2\\10x=140\\$

Dividing both sides by 10

$\frac{10x}{10}=\frac{140}{10}\\x=14$

Olivia sold 14 magazines.

Keywords: linear equations, division

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