Answer:
C.
Step-by-step explanation:
the answer is D. all of the above
Answer:
Area of trapezium = 4.4132 R²
Step-by-step explanation:
Given, MNPK is a trapezoid
MN = PK and ∠NMK = 65°
OT = R.
⇒ ∠PKM = 65° and also ∠MNP = ∠KPN = x (say).
Now, sum of interior angles in a quadrilateral of 4 sides = 360°.
⇒ x + x + 65° + 65° = 360°
⇒ x = 115°.
Here, NS is a tangent to the circle and ∠NSO = 90°
consider triangle NOS;
line joining O and N bisects the angle ∠MNP
⇒ ∠ONS =
= 57.5°
Now, tan(57.5°) = 
⇒ 1.5697 = 
⇒ SN = 0.637 R
⇒ NP = 2×SN = 2× 0.637 R = 1.274 R
Now, draw a line parallel to ST from N to line MK
let the intersection point be Q.
⇒ NQ = 2R
Consider triangle NQM,
tan(∠NMQ) = 
⇒ tan65° =
⇒ QM =
QM = 0.9326 R .
⇒ MT = MQ + QT
= 0.9326 R + 0.637 R (as QT = SN)
⇒ MT = 1.5696 R
⇒ MK = 2×MT = 2×1.5696 R = 3.1392 R
Now, area of trapezium is (sum of parallel sides/ 2)×(distance between them).
⇒ A = (
) × (ST)
= (
) × 2 R
= 4.4132 R²
⇒ Area of trapezium = 4.4132 R²
To find the median, find the middle number. Since there are 10 numbers, find the 5th one and the 6th one and find their average.
The two numbers are both 9, so its safe to say that the median is 9.
to find the median of the first and quartile, you have to place a line where the median should be and find the median of that. Q1 and Q2 will be 5 and 11 (respectively).
Its easy to see that all the lines start at the lowest point given and end at the largest point given, so match Q1, the median, and Q3
The only line that has lines at the Q1, median, and Q3 we figured out is answer C, so therefore it is the answer.
Answer:
1 and 2) After multiplying (x+y+3)(y+1) we have
Which is an equivalent expression after applying the distributive property.
As we can see we have an one of the variables squared, so we obtain an Parabolic Cillinder