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Rina8888 [55]
3 years ago
8

After painting the fence steve and janet realize that their house also needs painting. But steve will have to do the painting hi

mself since janet has injured her shoulder. Before getting started, steve wants to find out how long the project will take. He determines that it would take them 9 days to paint the house together (if they were both healthy) and that it would take janet (when healthy) 16 days to paint the house alone. How long will it take steve to paint the house alone?
Mathematics
1 answer:
gladu [14]3 years ago
4 0

Answer:

Therefore, Steve will paint house for 20.6 days.

Step-by-step explanation:

We know that Steve determines that it would take them 9 days to paint the house together (if they were both healthy) and that it would take Janet (when healthy) 16 days to paint the house alone.

We conclude that in 1 day Janet painted 1/16 of the house. In nine days, Janet painted 9/16 of house.

So, 7/16 of house paint Steve in nine days.

We have the following proportion:

\frac{7}{16}:9=1:x\\\\\frac{7}{16}x=9\\\\x=9\cdot \frac{16}{7}\\\\x=20.6

Therefore, Steve will paint house for 20.6 days.

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Find the midpoint of the line segment whose endpoints are (2.6,5.1) and (3,4.7).
svp [43]

Answer:

Mid point is: (2.8;4.9)

Step-by-step explanation:

To find midpoint of a line segment we can use the general equation:

Mid=\frac{x_1+x_2}{2} ;\frac{y_1+y_2}{2}

Where the point of the line are: (x₁;y₁) and (x₂;y₂).

In the problem, x₁ = 2.6, y₁ = 5.1 and x₂ = 3 and y₂ = 4.7. Replacing in the equation:

Mid=\frac{2.6+3}{2} ;\frac{5.1+4.7}{2}

<h3>Mid point is: (2.8;4.9)</h3>

7 0
3 years ago
3a x 5b x 7c = 39375, then find value of 7a - 2b + 3c​
garik1379 [7]

Answer:

Step-by-step explanation:

Simplifying

(7a + -2b) + -1[2(3a + -1c) + -3(2b + -3c)] = 0

Remove parenthesis around (7a + -2b)

7a + -2b + -1[2(3a + -1c) + -3(2b + -3c)] = 0

7a + -2b + -1[(3a * 2 + -1c * 2) + -3(2b + -3c)] = 0

7a + -2b + -1[(6a + -2c) + -3(2b + -3c)] = 0

7a + -2b + -1[6a + -2c + (2b * -3 + -3c * -3)] = 0

7a + -2b + -1[6a + -2c + (-6b + 9c)] = 0

Reorder the terms:

7a + -2b + -1[6a + -6b + -2c + 9c] = 0

Combine like terms: -2c + 9c = 7c

7a + -2b + -1[6a + -6b + 7c] = 0

7a + -2b + [6a * -1 + -6b * -1 + 7c * -1] = 0

7a + -2b + [-6a + 6b + -7c] = 0

Reorder the terms:

7a + -6a + -2b + 6b + -7c = 0

Combine like terms: 7a + -6a = 1a

1a + -2b + 6b + -7c = 0

Combine like terms: -2b + 6b = 4b

1a + 4b + -7c = 0

Solving

1a + 4b + -7c = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-4b' to each side of the equation.

1a + 4b + -4b + -7c = 0 + -4b

Combine like terms: 4b + -4b = 0

1a + 0 + -7c = 0 + -4b

1a + -7c = 0 + -4b

Remove the zero:

1a + -7c = -4b

Add '7c' to each side of the equation.

1a + -7c + 7c = -4b + 7c

Combine like terms: -7c + 7c = 0

1a + 0 = -4b + 7c

1a = -4b + 7c

Divide each side by '1'.

a = -4b + 7c

Simplifying

a = -4b + 7c

8 0
3 years ago
Help please thank you!!!!!!!!!!!!
Tom [10]

Step-by-step explanation:

ndndhsdjbdbdndndndndndnxndjdn there

5 0
2 years ago
A certain restaurant always overbooks. If possible. At 7:00 pm the restaurant can seat 50 parties, but takes reservations for 53
oee [108]

Answer:

The probability that the restaurant can accommodate all the customers who do show up is 0.3564.

Step-by-step explanation:

The information provided are:

  • At 7:00 pm the restaurant can seat 50 parties, but takes reservations for 53.
  • If the probability of a party not showing up is 0.04.
  • Assuming independence.

Let <em>X</em> denote the number of parties that showed up.

The random variable X follows a Binomial distribution with parameters <em>n</em> = 53 and <em>p</em> = 0.96.

As there are only 50 sets available, the restaurant can accommodate all the customers who do show up if and only if 50 or less customers showed up.

Compute the probability that the restaurant can accommodate all the customers who do show up as follows:

P(X\leq 50)=1-P(X>50)\\=1-P(X=51)-P(X=52)-P(X=53)\\=1-[{53\choose 51}(0.96)^{51}(0.04)^{53-51}]-[{53\choose 52}(0.96)^{52}(0.04)^{53-52}]\\-[{53\choose 53}(0.96)^{53}(0.04)^{53-53}]\\=1-0.27492-0.25377-0.11491\\=0.3564

Thus, the probability that the restaurant can accommodate all the customers who do show up is 0.3564.

7 0
3 years ago
MATH QUESTION: Julie bought a bag of parsnips that weighed 4 2/7 pounds. She also bought a bag of turnips that weighed 1 1/3 tim
kati45 [8]

Answer:

Julie buy 5\frac{5}{7} pounds of turnips.

Step-by-step explanation:

We are given that Julie bought a bag of parsnips that weighed (4\frac{2}{7}) pounds. She also bought a bag of turnips that weighed (1\frac{1}{3}) times as much as the parsnips.

We have to find how many pounds of turnips did Julie buy.

Firstly, the weight of a bag of parsnips that Julie bought = 4\frac{2}{7} = \frac{30}{7} pounds

Now, it is stated that she bought a bag of turnips that weighed (1\frac{1}{3}) times as much as the parsnips, that means;

Weight turnips bag = \frac{4}{3} \times \frac{30}{7}

                              = 4 \times \frac{10}{7}

                              = \frac{40}{7}

So, Julie buy 5\frac{5}{7} pounds of turnips.

5 0
3 years ago
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