Let f(x) = 6x. Find f(3)
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Answer:
67/4
Step-by-step explanation:
Let C, D be the line segments that join (-1,0) with (0,8) and (0,8) with (2,8) respectively.
The work required by the force field F(x,y)=(x,y) is the curve integral
the line segments that joins (-1,0) with (0,8) can be parameterized as
<em>r(t) = t(0,8)+(1-t)(-1,0)=(t-1,8t) with 0≤ t≤ 1 </em>
So
the line segments that joins (0,8) with (2,8) can be parameterized as
<em>r(t) = t(2,8)+(1-t)(0,8)=(2t,8) with 0≤ t≤ 1 </em>
hence
and we have the work required by F to move a particle alon the path is