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Ugo [173]
3 years ago
7

Using a scale factor, how tall will the actual building be?

Mathematics
1 answer:
Katarina [22]3 years ago
4 0

Answer:

OPTION C: 105 ft.

Step-by-step explanation:

Note that the width of the building in the map is 3 ft.

The width of the actual building is 45 ft.

That means, the actual building is 15 times more than the map, since, $ 15 \times 3 = 45 $.

Therefore, the height of the actual building would be 7 X 15 = 105 ft.

Hence, the height of the actual building is 105 ft. which is OPTION C.

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mina [271]
Notice the picture below

\bf \textit{equation of a circle}\\\\
(x-{{ h}})^2+(y-{{ k}})^2={{ r}}^2
\qquad center\ ({{ h}},{{ k}})\qquad
radius={{ r}}\\\\
-----------------------------\\\\
\textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
&({{ 1}}\quad ,&{{ 4}})\quad 
%  (c,d)
&({{ 4}}\quad ,&{{ 8}})
\end{array}\qquad 
%  distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}\leftarrow r

you have the center, the h,k, all  you really need is the radius "r"


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Your current schedule only lets you take two 1-credit courses every six months. You need 12 credits to get the degree you want.
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So,

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The lines represented by the equations 12y – 8x = -72 and y = 2/3 x – 3
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Answer:

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