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2 years ago

Find BD. help me pls

Mathematics

1 answer:

Anna [14]2 years ago

5 0

Answer:

Step-by-step explanation:

We can see that Ar is the perpendicular bisector of chord BD. Since A is the center of the circle, AR is the radius of the circle, which is 10 (6+4)

Next, we can see that when we connect point A to point D, it is also a radius. Thus, AD is also equal to 10 as the radius of the circle remains the same.

Using Pythagoras theorem, a^2 + b^2 = c^2, we can make a right angled triangle of ACD.

AC = 6 = a

CD = ? = b

AD = 10 = c

10^2 = 6^2 + b^2

b^2 = 10^2 - 6^2 = 64

b = CD = 8

Now, since Ar is the perpendicular bisector of chord BD, BD = CD x 2

BD = 8 x 2 = <u>16</u>

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