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Molodets [167]
2 years ago
6

Find BD. help me pls

Mathematics
1 answer:
Anna [14]2 years ago
5 0

Answer:

16

Step-by-step explanation:

We can see that Ar is the perpendicular bisector of chord BD. Since A is the center of the circle, AR is the radius of the circle, which is 10 (6+4)

Next, we can see that when we connect point A to point D, it is also a radius. Thus, AD is also equal to 10 as the radius of the circle remains the same.

Using Pythagoras theorem, a^2 + b^2 = c^2, we can make a right angled triangle of ACD.

AC = 6 = a

CD = ? = b

AD = 10 = c

10^2 = 6^2 + b^2

b^2 = 10^2 - 6^2 = 64

b = CD = 8

Now, since Ar is the perpendicular bisector of chord BD, BD = CD x 2

BD = 8 x 2 = <u>16</u>

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Serggg [28]

Answer:

-65

Step-by-step explanation:

use Khan academy it's very helpful

7 0
3 years ago
Read 2 more answers
Geometry question. please help ​
Vinvika [58]

Answer:

The length of PQ is <u>18</u> feet.

The length of PR is <u>18</u> feet.

The length of QR is <u>24</u> feet.

Step-by-step explanation:

A way to set an equation up for this problem is:

\frac{4}{3}x+x+x=60

where x is the three lengths of the isosceles triangle, but the base QR is 4/3 the length of the other two congruent sides, length PQ and PR. The 60 represents the total length of the perimeter.

Then, solve for x from the equation, and you’ll get x=18. But your not done yet. Since the variable x in the equation stands for the sides of the isosceles triangle, so plug 18 into the equation and it should look like this:

\frac{4}{3}(18)+18+18=60

Don’t solve the whole equation, just solve the \frac{4}{3}(18) part of the equation, which is equal to 24. So the final equation is this:

24+18+18=60

Conclusion: 24 is the length of QR, and 18 is the length of PQ and PR. And they all equal 60, which is the perimeter. This is very true because the length of PQ and PR are the same (length 18), since it’s an isosceles triangle, and the length of QR is 4/3 the length of PQ and PR (4/3 of 18= 24).

Sorry for the long explanation.

But hope this helps and answers your question :)

8 0
3 years ago
I have a series of 2 questions.
Margarita [4]
1)
I:y=3x-4
II:9x-3y=14


substitute y into II:
9x-3*(3x-4)=14
9x-9x+12=14
12=14

this is obviously not equal so there is no solution, the lines are parallel

2)
I:y=4x+6
II:5x-y=6

substitute y into II:
5x-(4x+6)=6
5x-4x-6=6
x=12
substiute x into II:
5*12-y=6
-y=6-60
-y=-54
y=54

the solution is (12,54)
3 0
3 years ago
Which graph best represents a functionwith zeros of -3, 0, and 2?
torisob [31]

Answer:

0

Step-by-step explanation:

5 0
3 years ago
Help with the problem
KiRa [710]

Answer:

Not clear of the question

Step-by-step explanation:

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