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Katen [24]
3 years ago
11

the ratio of red marbles to blue marbles in a bag is 2 to 3 .which of the following could be the number of red and blue marbles

in the bag ​
Mathematics
1 answer:
Nataliya [291]3 years ago
8 0

Answer

Picture? what is the following

Step-by-step explanation:

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∠A and ∠ B ∠B are vertical angles. If m ∠ A = ( 3 x − 21 ) ∘ ∠A=(3x−21) ∘ and m ∠ B = ( 2 x − 13 ) ∘ ∠B=(2x−13) ∘ , then find th
Sav [38]

Answer:

x=8

Step-by-step explanation:

start by setting angle a equal to angle b

next add 21 to the opposite side

then subtract 2x from the opposite side

finally you're left with x=8

3 0
3 years ago
Point Mis the midpoint of AB. AM = 3x + 3, and AB= 83 – 6.
Ber [7]

Answer:

AM= Half of AB

or, 3x+3=(8x-6)/2

or, 6x+6=8x-6

or, 2x=12

Therefore,x=6

so,AM=3*6+3=21

So the units is 21

4 0
3 years ago
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Write an equivalent fraction for each give fraction 10/2​
irakobra [83]

Answer:

5/1

Step-by-step explanation:

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2 years ago
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MakcuM [25]

Answer:It has to be more clear

Step-by-step explanation:

3 0
2 years ago
A certain disease has an incidence rate of 0.5%. The false negative rate on a test for the disease is 5%; the false positive rat
expeople1 [14]

Using conditional probability, it is found that the probability a person who tests positive actually has the disease is 0.087 = 8.7%.

<h3>What is Conditional Probability?</h3>

Conditional probability is the probability of one event happening, considering a previous event. The formula is:

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which:

  • P(B|A) is the probability of event B happening, given that A happened.
  • P(A \cap B) is the probability of both A and B happening.
  • P(A) is the probability of A happening.

For this problem, the events are given as follows:

  • Event A: Positive test.
  • Event B: Person has the disease.

The percentages associated with a positive test is:

  • 95% of 0.5%(person has the disease).
  • 5% of 99.5%(person does not have the disease).

Hence:

P(A) = 0.95 x 0.005 + 0.05 x 0.995 = 0.0545.

The probability of both a positive test and having the disease is:

P(A \cap B) = 0.95 \times 0.005 = 0.00475

Hence the conditional probability is:

P(B|A) = 0.00475/0.0545 = 0.087.

The probability a person who tests positive actually has the disease is 0.087 = 8.7%.

More can be learned about conditional probability at brainly.com/question/14398287

#SPJ1

3 0
1 year ago
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