1 year ago

Given the graph, which coordinate point is NOT a solution?

Mathematics

1 answer:

Natasha2012 [34]1 year ago

6 0

Answer: (1, 2) (The third option)

Step-by-step explanation: A solution has to be on the line. (1, 2) is the only point that isn't on the line.

You might be interested in

For a snack, sameer ate a plum with 32 calories and several strawberries with 4 calories each. if the total number of calories i

Westkost [7]

Total calories = 56
Amount of calories in plum = 32
Remaining Calories = 56 - 32 = 24
Amount of calories with one strawberry = 4
No. of strawberries he ate = 24/4 = 6 strawberries

I hope it is helpful:D

6 0

2 years ago

Read 2 more answers

Thuy has $625 in her checking account she writes two checks for $23 each and then makes one deposit of $146 what is thuy’s final

aksik [14]

$456$.$.$.$$.&.&.&.&.&.$.$.$.$$.$.$.$.$.$.$.$.$.$$.$.$.$&.

5 0

2 years ago

Read 2 more answers

The zeros of a parabola are –4 and 2, and (6, 10) is a point on the graph. Which equation can be solved to determine the value o

Fittoniya [83]

$\bf ~~~~~~\textit{parabola vertex form}
\\\\
\begin{array}{llll}
y=a(x- h)^2+ k\\\\
x=a(y- k)^2+ h
\end{array}
\qquad\qquad
vertex~~(\stackrel{}{ h},\stackrel{}{ k})\\\\
-------------------------------\\\\
\stackrel{\textit{zeros\qquad \qquad \qquad }}{
\begin{cases}
x=-4\implies &x+4=0\\
x=2\implies &x-2=0
\end{cases}}
\\\\\\
\stackrel{\textit{factored vertex form}}{y=a(x+4)(x-2)}\qquad (6,10)\textit{ we also know that }
\begin{cases}
x=6\\
y=10
\end{cases}
\\\\\\
10=a(6+4)(6-2)$