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9966 [12]
3 years ago
6

= 39 newspapers in 3 piles newspapers per pile

Mathematics
2 answers:
Mama L [17]3 years ago
8 0

Answer:

there are 13 newspapers per pile

Step-by-step explanation:

to find newspapers per pile we divide 39/ 3

39/3= 13

dalvyx [7]3 years ago
7 0
13 newspapers per pile
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Which of the following side lengths can form a triangle?
Margaret [11]

Okay, so my last answer was deleted because I didnt show any work.


According to the rule,


a+b>c

c+b>a

c+a>b


so...


2+3=6...6<7

21+23=44...44+44

12+36=48...48<53

14+17=31...31>30


Since answer D is the only answer that fullfills the rule a+b>c, it is the correct answer


3 0
4 years ago
Read 2 more answers
Equation that represents the line that passes through the point (-2,-1) and has a slope of 5
ss7ja [257]
Straight line:
y = mx + c
m is the slope of the graph and c is the y-intercept
In this case, m = 5 as stated in the question, so...
y = 5x + c
By substituting the given co-ordinates (-2,-1) into this equation, we can find c
-1 = 5(-2) + c
-1 = -10 + c
-1 + 10 = -10 + c + 10 (Add 10 to both sides)
9 = c
c = 9
Put c = 9 into the equation:
y = 5x + 9
5 0
3 years ago
Machine A prints 16 pages more than Machine B in every minute. Machine A and Machine B print a total of 608 pages in 4 minutes.
sweet [91]

1) So the ratio of Machine A to B is x + 16 : x (x being the paper printed in machine b).

2) This is in 4 minutes so every minute it will be 152.

2) So x + 16 + x = 152, or 2x + 16 = 152.

3) So to find x, we can subtract 16 from both sides. 2x = 136

4) Now we just divide both sides by 2 to get x = 68.

5) So machine A will be 68 + 16 = 84.

=  84

⭐ Answered by Foxzy0⭐

⭐ Brainliest would be appreciated, I'm trying to reach genius! ⭐

⭐ If you have questions, leave a comment, I'm happy to help! ⭐

3 0
2 years ago
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Find the optimal solution for the following problem. (Round your answers to 3 decimal places.)
irina1246 [14]

Answer:

Maximize C =9x + 7y

8x + 10y \leq 17

11x + 12y\leq 25

and x ≥ 0, y ≥ 0

Plot the lines on graph

8x + 10y \leq 17

11x + 12y\leq 25

x\geq 0

y\geq 0

So, boundary points of feasible region are (0,1.7) , (2.125,0) and (0,0)

Substitute the points in  Maximize C

At  (0,1.7)

Maximize C =9(0) + 7(1.7)

Maximize C =11.9

At  (2.125,0)

Maximize C =9(2.125) + 7(0)

Maximize C =19.125

At   (0,0)

Maximize C =9(0) + 7(0)

Maximize C =0

So, Maximum value is attained at   (2.125,0)

So, the optimal value of x is 2.125

The optimal value of y is 0

The maximum value of the objective function is 19.125

4 0
3 years ago
What is the function doing in the interval -3 7 poin<br> Decreasing<br> Increasing
disa [49]

Answer:

increasing

Step-by-step explanation:

6 0
3 years ago
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