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alexdok [17]
3 years ago
10

I need the answer. Please help.

Mathematics
1 answer:
Marysya12 [62]3 years ago
7 0

Using the Pythagorean theorem:

WY =√(5^2 + 12^2)

WY = √(25 +144)

WY = √169

WY = 13 mm

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|a|-3/4=-5/8 Solve and show your work?
Marta_Voda [28]

Answer:

{-1/8, 1/8}

Step-by-step explanation:

Solve |a|-3/4=-5/8 for |a|:  Add 3/4 to both sides of this equation, obtaining:

|a| - 6/8 + 6/8 = -5/8 + 6/8, or |a| = 1/8.  This absolute value function has two components:

a = 1/8 and a = -1/8.


7 0
3 years ago
A machine lifts up containers of coal from the mine and lowers empty containers down. The machine uses an electric motor connect
Shkiper50 [21]

Answer:

The maximum power available to the motor is 2.4 MW

Step-by-step explanation:

The power of  a circuit that has a current, I, and a voltage, V, is given by the relation

Electrical power, P = I²R = I× I×R = I × V

Therefore given that the parameters are;

Voltage in the d.c. power supply = 600 V d.c.

Maximum current in the motor = 4000 A

Therefore, we can find the power as follows;

Maximum motor power = Voltage × Current

The maximum motor power, P available =  600 V × 4000 A = 2400000 W which on converting to MW becomes;

The maximum power available to the motor , P = 2.4 MW.

4 0
2 years ago
How can you tell if the expression 7x-4 and 6x-4-x are equivalent
olga_2 [115]

Answer:

see below

Step-by-step explanation:

7x-4          6x-4-x

Combine like terms on the second expression

7x -4          6x -x -4

                 5x -4

These are not equivalent  expressions

7x -4  does not equal 5x-4

8 0
2 years ago
I need help asappp please, I attached a image​
k0ka [10]

Answer:

Just look at the other answer

Step-by-step explanation:

7 0
1 year ago
4. A solution of 60% fertilizer is to be mixed with a solution of 21% fertilizer to form 234 liters of a 43% solution. How many
solniwko [45]

Given:

A solution of 60% fertilizer is to be mixed with a solution of 21% fertilizer to form 234 liters of a 43% solution.

To find:

The quantity of the 60% solution in the mixture.

Solution:

Let x be the quantity of the 60% solution and y be the quantity of the 21% solution.

Quantity of mixture is 234. So,

x+y=234

x=234-y                  ...(i)

The mixture has 43% fertilizer. So,

\dfrac{60}{100}x+\dfrac{21}{100}y=\dfrac{43}{100}\times 234

Multiply both sides by 100.

60x+21y=10062            ...(ii)

Using (i) and (ii), we get

60(234-y)+21y=10062

14040-60y+21y=10062

-39y=10062-14040

-39y=-3978

Divide both sides by -39.

\dfrac{-39y}{-39}=\dfrac{-3978}{-39}

y=102

Putting this value in (i), we get

x=234-102

x=132

Therefore, 132 liters of the 60% solution must be used.

3 0
2 years ago
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