Answer: 
Step-by-step explanation:
Given
Points are 
Convert mixed numeral to fraction

Slope of the line is

Equation of line

Answer:
This is always ''interesting'' If you see an absolute value, you always need to deal with when it is zero:
(x-4)=0 ===> x=4,
so that now you have to plot 2 functions!
For x<= 4: what's inside the absolute value (x-4) is negative, right?, then let's make it +, by multiplying by -1:
|x-4| = -(x-4)=4-x
Then:
for x<=4, y = -x+4-7 = -x-3
for x=>4, (x-4) is positive, so no changes:
y= x-4-7 = x-11,
Now plot both lines. Pick up some x that are 4 or less, for y = -x-3, and some points that are 4 or greater, for y=x-11
In fact, only two points are necessary to draw a line, right? So if you want to go full speed, choose:
x=4 and x= 3 for y=-x-3
And just x=5 for y=x-11
The reason is that the absolute value is continuous, so x=4 works for both:
x=4===> y=-4-3 = -7
x==4 ====> y = 4-11=-7!
abs() usually have a cusp int he point where it is =0
Step-by-step explanation:
Answer:
x = 6
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtract Property of Equality
<u>Algebra I</u>
- Terms/Coefficients/Degrees
- Expand by FOIL (First Outside Inside Last)
- Factoring
- Multiple Roots
<u>Trigonometry</u>
[Right Triangles Only] Pythagorean Theorem: a² + b² = c²
- a is a leg
- b is another leg
- c is the hypotenuse
Step-by-step explanation:
<u>Step 1: Identify</u>
<em>a</em> = x + 3
<em>b</em> = x
<em>c</em> = √117
<u>Step 2: Solve for </u><em><u>x</u></em>
- Substitute [PT]: (x + 3)² + x² = (√117)²
- Expand [FOIL]: x² + 6x + 9 + x² = (√117)²
- Combine like terms: 2x² + 6x + 9 = (√117)²
- Exponents: 2x² + 6x + 9 = 117
- [SPE] Subtract 117 on both sides: 2x² + 6x - 108 = 0
- Factor out GCF: 2(x² + 3x - 54) = 0
- [DPE] Divide 2 on both sides: x² + 3x - 54 = 0
- Factor Quadratic: (x - 6)(x + 9) = 0
- Solve roots/solve <em>x</em>: x = -9, 6
Since we are dealing with positive values, we can disregard the negative root.
∴ x = 6