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Alex73 [517]
2 years ago
6

Bag has 2 blue marbles, 3 red marbles, and 5 white marbles. Which events have a probability greater than One-fifth? Select three

options.
choosing 1 blue marble
choosing 1 red marble
choosing 1 red marble, not replacing it, and then choosing a blue marble
choosing 1 white marble, replacing it, and choosing another white marble
choosing 1 white marble
Mathematics
1 answer:
dimulka [17.4K]2 years ago
7 0

Answer:

choosing 1 red marble

choosing 1 white marble, replacing it, and choosing another white marble

choosing 1 white marble

Step-by-step explanation:

red marble has a 30 percent chance

1 white marble and then replacing and another white marble is 25% chance

1 white marble is 50% chance

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if p is an integer, which of the following is the solution set for 2|p| = 16? {0, 8} {-8, 8} {-8, 0} {-8, 0, 8}
Veronika [31]
2|p|=16\ \ \ |divide\ both\ sides\ by\ 2\\\\|p|=8\iff p=8\ or\ p=-8\\\\Answer:\boxed{\{-8;\ 8\}}
8 0
3 years ago
Distributed Property<br><br> Please simplify 5(-x-4)-4 <br><br> thanks
den301095 [7]
It’ll be -5x - 24

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5 0
3 years ago
The accounting records of Blossom Company show the following data. Beginning inventory 3,090 units at $5 Purchases 7,930 units a
meriva

Answer:

The cost of goods sold is 65,850

Step-by-step explanation:

FIFO Perpetual chart is attached.

FIFO Perpetual chart shows purchases, sales and balance of  the period.

The cost of goods sold is:

3,090 units x $5=$15,450

6,300 units x $8=$50,400

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Download xlsx
6 0
3 years ago
PLEASE HELP
Anastasy [175]

Answer:

3

Step-by-step explanation:

the line crosses the y-axis at (0,3)

3 0
3 years ago
Read 2 more answers
NEED HELP HERE ASAP<br><br> 6. Find the cube roots of 27(cos 330° + i sin 330°).
VLD [36.1K]
<span>we have that

the cube roots of 27(cos 330° + i sin 330°) will be
</span>∛[27(cos 330° + i sin 330°)]

we know that
e<span>^(ix)=cos x + isinx
therefore
</span>∛[27(cos 330° + i sin 330°)]------> ∛[27(e^(i330°))]-----> 3∛[(e^(i110°)³)]
3∛[(e^(i110°)³)]--------> 3e^(i110°)-------------> 3[cos 110° + i sin 110°]

z1=3[cos 110° + i sin 110°]

 cube root in complex number, divide angle by 3
360nº/3 = 120nº --> add 120º for z2 angle, again for z3
<span>therefore
</span>
z2=3[cos ((110°+120°) + i sin (110°+120°)]------ > 3[cos 230° + i sin 230°]

z3=3[cos (230°+120°) + i sin (230°+120°)]--------> 3[cos 350° + i sin 350°]
<span>
the answer is 

</span>z1=3[cos 110° + i sin 110°]<span>

</span>z2=3[cos 230° + i sin 230°]

z3=3[cos 350° + i sin 350°]<span>

</span>
7 0
3 years ago
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