10a. y= 35x + 60
10b. $165
x=4 would be a vertical line
Answer:
Sheridan's Work is correct
Step-by-step explanation:
we know that
The lengths side of a right triangle must satisfy the Pythagoras Theorem

where
a and b are the legs
c is the hypotenuse (the greater side)
In this problem
Let

substitute

Solve for b





we have that
<em>Jayden's Work</em>


substitute and solve for c





Jayden's Work is incorrect, because the missing side is not the hypotenuse of the right triangle
<em>Sheridan's Work</em>


substitute

Solve for b





therefore
Sheridan's Work is correct
Answer:
Step-by-step explanation:
First, look at y = log x. The domain is (0, infinity). The graph never touches the vertical axis, but is always to the right of it. A real zero occurs at x = 1, as log 1 = 0 => (1, 0). This point is also the x-intercept of y = log x.
Then look at y = log to the base 4 of x. The domain is (0, infinity). The graph never touches the vertical axis, but is always to the right of it. Again, a real zero occurs at x = 1, as log to the base 4 of 1 = 0 => (1, 0).
Finally, look at y=log to the base 4 of (x-2). The graph is the same as that of y = log to the base 4 of x, EXCEPT that the whole graph is translated 2 units to the right. Thus, the graph crosses the x-axis at (3, 0), which is also the x-intercept.